Polyval input when manual value

5 vues (au cours des 30 derniers jours)
Benjamin
Benjamin le 5 Jan 2015
Modifié(e) : dpb le 5 Jan 2015
Hi, I create a first 3*5 matrix using polyfit() corresponding to 3 curves
for xx=1:length(pix_x)
y=BrightTN(:,pixels(xx));
p=polyfit(x,y,4);
P(xx,:)=p(1,:);
y1= polyval(p,x);
plot(x,y1,Color(xx))
end
When using polyval() on these, everything fine, i get value between 0 and 1.
R=zeros(134,3);x=sigma;
R(:,1)= polyval(P(1,:),x);
R(:,2)= polyval(P(2,:),x);
R(:,3)= polyval(P(3,:),x);
If a create a matrix by manually entering same value , polyval() return bad value between -38 and 64, i don't understand why.
P2=[-1.9563e-10 8.8342e-7 -0.0015 1.0858 -296.2330;
4.8228e-10 -2.0601e-6 0.0033 -2.2701 585.5897;
-3.7439e-10 1.7088e-6 -0.0029 2.1705 -602.1542;];
  2 commentaires
David Young
David Young le 5 Jan 2015
Maybe the values are different. What do you see with
disp(P - P2);
?
dpb
dpb le 5 Jan 2015
Modifié(e) : dpb le 5 Jan 2015
No way we can tell; you don't show any variable x in the first loop and we don't have your raw data.
But, polyval is deterministic with the same inputs, so at_least_one of the inputs to it is different between the two cases.

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