Error ' Index in position 2 exceeds array bounds'.how to correct this.

When run it, shows

"Index in position 2 exceeds array bounds. Index

must not exceed 2.

Error in practice (line 20)

while(abs(a(k)-a(k-1))>=0.01) && abs(b(k)-b(k-1))>=0.01 && rms(abs(A(:,k)-A(:,k-1)))>=0.01"

Please help to correct this?

Answer 1

[Geoff Hayes]

@susan sara - in your while loop conditions

while(abs(a(k)-a(k-1))>=0.01) && abs(b(k)-b(k-1))>=0.01  && rms(abs(A(:,k)-A(:,k-1)))>=0.01

you have

rms(abs(A(:,k)-A(:,k-1)))

. At the end of the loop you do

k=k+1;

. I don't see anywhere in the code where you update A for k+1 and so I suspect the error message is originating when indexing into A on the second iteration of the loop when k is 3. You may want to review this code

for j=x(1):1:x(length(i))
    A(j,k)=((H(j))/(a(k)))-1    
    for j=y(1):1:y(length(i))
        A(j,k)=((H(j))/(b(k)))-1      
    end
    for j=z(1):1:z(length(i))
        A(j,k)=G(j)         
    end

Is the above correct? Is there a missing end for the first for loop?