Getting the entry value (i,j) for the minimum value of reach row of a matrix

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Wietze Zijpp
Wietze Zijpp le 9 Avr 2022
Commenté : Voss le 9 Avr 2022
Suppose I have a matrix
A = 3×3
11 13 15
12 14 16
32 18 21
How do I get the output (1,1) (2,1) and (1,3) which indicate the position of the minimum value of each row.

Réponse acceptée

Voss
Voss le 9 Avr 2022
A=[11 13 15
12 14 16
32 18 21];
[minrow,idx] = min(A,[],2) % min value of each row, with column index
minrow = 3×1
11 12 18
idx = 3×1
1 1 2
result = [(1:size(A,1)).' idx] % 18 is at (3,2) not (1,3)
result = 3×2
1 1 2 1 3 2
  2 commentaires
Wietze Zijpp
Wietze Zijpp le 9 Avr 2022
Thank you, this is what I was looking for

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Plus de réponses (1)

Arif Hoq
Arif Hoq le 9 Avr 2022
may be you are looking for this:
A=[11 13 15
12 14 16
32 18 21];
mincol=min(A) % min value of each column
mincol = 1×3
11 13 15
minrow= min(A,[],2) % min value of each row
minrow = 3×1
11 12 18
  3 commentaires
Arif Hoq
Arif Hoq le 9 Avr 2022
Modifié(e) : Arif Hoq le 9 Avr 2022
if you want fine the row,column of minimum of each row, then
A=[11 13 15
12 14 16
32 18 21];
mincol=min(A) % min value of each column
mincol = 1×3
11 13 15
minrow= min(A,[],2) % min value of each row
minrow = 3×1
11 12 18
[row col]=find(ismember(A,minrow))
row = 3×1
1 2 3
col = 3×1
1 1 2
% here A(1,1)=11 >> A(2,1)=12 >> A(3,2)=18
Wietze Zijpp
Wietze Zijpp le 9 Avr 2022
This is what I was looking for, thank you.

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