
Getting a solution for two coupled nonlinear differential equations
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sardar peysin
le 12 Avr 2022
Commenté : sardar peysin
le 12 Avr 2022
Hello dears. I am looking for the solutions for y(t) and z(t) in two coupled differential equations simultaneously. I need solutions for each of y and z as the equations (for example y=C1 exp (A/B)t or z=C1 exp (B//A)t) not as numbers if it is possible.
At least, an Approximate Analytical Solution is desired, which may be achievable with the generation of sufficient dot points and the Curve-Fitting Toolbox.
- ODE of the nonlinear system,
- constant values of A and B,
- initial values of y0 and z0.

Both y(t) and z(t) are functions of t. Here, A and B are constant values. We want to get a solution for each of the dependent variables of y(t) and z(t). If it is needed the initial values of y0=y(0) and z0=z(0) can be used to achieve the solution.
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Réponse acceptée
Sam Chak
le 12 Avr 2022
Modifié(e) : Sam Chak
le 12 Avr 2022
Please check if this works out for your study:
A = 1.0;
B = 1.0;
fun = @(t, x)[-A*x(1)*x(2)^4; % 1st ODE
-B*x(1)^2*x(2)^3]; % 2nd ODE
tspan = [0 1e2];
y0 = 1.0; % initial value of y(t)
z0 = 1.125*y0; % initial value of z(t)
x0 = [y0;
z0];
[T, Z] = ode45(fun, tspan, x0); % Solver assigns solutions to Z array
y = Z(:,1); % numerical solution for y(t)
z = Z(:,2); % numerical solution for z(t)
% Fit well if A = 1; B = 1, and A = 1; B = -1
f1 = fit(T, y, 'rat23') % fit Rat23 model into y(t) data
f2 = fit(T, z, 'rat33') % fit Rat33 model into z(t) data
% Fit well if A = -1; B = 1
% f1 = fit(T, y, 'rat22') % fit Rat22 model into y(t) data
% f2 = fit(T, z, 'rat22') % fit Rat22 model into z(t) data
subplot(2, 1, 1)
plot(f1, T, y)
subplot(2, 1, 2)
plot(f2, T, z)
The Approximate Analytical Solution is a Rational Function:
f1 =
General model Rat23:
f1(x) = (p1*x^2 + p2*x + p3) /
(x^3 + q1*x^2 + q2*x + q3)
Coefficients (with 95% confidence bounds):
p1 = 1.925 (1.768, 2.083)
p2 = -0.4781 (-0.9759, 0.01979)
p3 = -0.246 (-0.5008, 0.008754)
q1 = 2.363 (1.718, 3.009)
q2 = -0.9528 (-1.554, -0.3518)
q3 = -0.2443 (-0.5014, 0.01292)
f2 =
General model Rat33:
f2(x) = (p1*x^3 + p2*x^2 + p3*x + p4) /
(x^3 + q1*x^2 + q2*x + q3)
Coefficients (with 95% confidence bounds):
p1 = 0.5208 (0.5195, 0.5221)
p2 = 12.22 (10.04, 14.4)
p3 = 50.82 (43.67, 57.96)
p4 = 21.52 (18.88, 24.16)
q1 = 24.87 (20.4, 29.34)
q2 = 68.33 (59.2, 77.46)
q3 = 19.15 (16.8, 21.5)
Results:

6 commentaires
Sam Chak
le 12 Avr 2022
Thank you for your acceptance. Of course you may ask. This is a forum for users to discuss matters related to Mathworks products and to help each other. By the way, I have also edited the Answer to add a little more info on the code about the selection of the Rational function models.
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sardar peysin
le 12 Avr 2022
4 commentaires
Sam Chak
le 12 Avr 2022
I also learn from examples.
To give an example why another Rational model should be chosen, let say we select
A = -1;
B = 1;
then the previous proposed Rational model (Rat23) does not fit well for y(t).

So, by trial-and-error, it is found that Rat22 model fits well for both y(t) and z(t) in this case.
f1 = fit(T, y, 'rat22') % fit Rat22 model into y(t) data
f2 = fit(T, z, 'rat22') % fit Rat22 model into z(t) data

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