Attempted to access x(402); index out of bounds because numel(x)=401.

1 vue (au cours des 30 derniers jours)
Hassan
Hassan le 10 Jan 2015
Commenté : Stephen23 le 10 Jan 2015
I want to apply forward downstream scheme on a linear advection equation; this code was used in forward upstream scheme and I could not modify it to fit my application.
The error is caused by the "k+1" in line 18 of the code
dx = 0.05; dt = 0.01; C = 1; A1 = 1-C*dt/dx; A2 = C*dt/dx;
x = [0:dx:20];
N = length(x);
for k = 2:N
if (x(k) >= 4) && (x(k) <= 6)
u(k) = cos(0.5*pi*(x(k)-5));
else
u(k) = 0;
end
end
u(1) = u(N);
for k = 1:N
uplot(1,k) = u(k);
end
for iout = 1:5
for n = 1:5
for k = 2:N
u1(k) = A1*u(k)+A2*u(k+1);
end
u1(1) = u1(N);
for k = 1:N
u(k) = u1(k);
end
end
for k = 1:N
uplot(iout+1,k) = u(k);
end
end

Réponse acceptée

Stalin Samuel
Stalin Samuel le 10 Jan 2015
instead of N use N-1
  2 commentaires
Hassan
Hassan le 10 Jan 2015
In which line?
Stephen23
Stephen23 le 10 Jan 2015
Line 17: for k = 2:N-1.

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by