How to implement a sliding window with a condition

The code is supposed to show 1 when residual deviates beyond the threshold for x consecutive sample times and 0 when deviates once after y sampling time. The residual is a column matrix 2000 x1 . I tried using a sliding window approach to achieve this.

[Jan]

Please post, what you have tried so far and explain, what is not working as wanted. A small example would be useful also to understand, what you want. E.g. what does "show 1" mean? What is "sampling time"?

[Kwaku Junior]

i tried using a sliding window to count the faults ( 1) in a specific time period . for example 0 to 400 , then 401 to 800. Then plot a rectangular pulse .

left = 0;

right = 0;

k = 400; %% sample = 5s / 0.0125 interval

windcount = 0;

while ( right<k )

windcount = windcount + fault(right+1);

right = right + 1;

end

while right < size(Threshold)

windcount = windcount + fault(right+1) - fault(left+1);

for i=size(Threshold)

if (fault(i) == 1)

windcount = windcount +1 ;

disp(windcount)

end

end

left = right

right = right +400

end

disp('while')

if windcount > 250

fault2(i) = 1;

else

fault2(i) = 0;

end

disp('Plotting')

plot(Time, fault2)

Answer 1

[DGM]

You can probably just use movmin().

R = rand(100,1);
th = 0.5;
w = 2;

exceeds_th = movmin(R,w)>th;
[R exceeds_th]

ans = 100×2

0.3394 0 0.7952 0 0.6381 1.0000 0.4328 0 0.2726 0 0.7042 0 0.7297 1.0000 0.3039 0 0.1256 0 0.1311 0

You can play around with the options for movmin() to adjust how it behaves.

[Kwaku Junior]

Thank You, i tried this but it didnt give me the results i wanted. 'if a fault occurs or goes beyond a certain threshold for a consecutive number of times , show 1 ' this is the result i wanted