Arrayfun with multiple variable?

Hi, probably this question has already received answers but what I found don't solve my problem.
I know that I have a function that requires one input i can use arrayfun like this:
A=arrayfun(@functionExample, input1);
But if I have a function that requires more than one input how can I do?
Thanks

Réponses (2)

Voss
Voss le 19 Avr 2022

0 votes

Two inputs:
A=arrayfun(@(x,y)functionExample(x,y), input1, input2);
Three inputs:
A=arrayfun(@(x,y,z)functionExample(x,y,z), input1, input2, input3);
And so on.

3 commentaires

MementoMori
MementoMori le 19 Avr 2022
Thank you.
But I have this error:
Variable number of inputs is not supported.
For more information see Tips.
MementoMori
MementoMori le 19 Avr 2022
Is this caused by varargin in the function "functionExample"
It is not required to use anonymous functions, a simple function handle works with any number of inputs:
V = arrayfun(@max,[1,2,3],[0,9,0])
V = 1×3
1 9 3

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Stephen23
Stephen23 le 19 Avr 2022
Modifié(e) : Stephen23 le 19 Avr 2022
"But if I have a function that requires more than one input how can I do?"
ARRAYFUN already works with any number of input arrays:
fnh = @(varargin)sum([varargin{:}]); % test function, any number of inputs
arrayfun(fnh,[1,2,3])
ans = 1×3
1 2 3
arrayfun(fnh,[1,2,3],[4,5,6])
ans = 1×3
5 7 9
arrayfun(fnh,[1,2,3],[4,5,6],[7,8,9])
ans = 1×3
12 15 18

Modifié(e) :

le 19 Avr 2022

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