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Effacer les filtres

Split an Array in sub-arrays based on the first number in the column

3 vues (au cours des 30 derniers jours)
Fabio Taccaliti
Fabio Taccaliti le 19 Avr 2022
Commenté : Stephen23 le 20 Avr 2022
Hello,
I have an array M 2939x4 that I would like to split in sub-arrays based on the number in the first column.
I mean in the first colunm a number is listed, first 0, then 0.02, then 0.04 and so on (with an increment of 0.02) until 2.2, the problem is that the times that this number appear is not always the same (for example the 0 is on the first 28 rows, the 0.02 in the following 24 and the 0.04 in the next 29).
My idea was to find the number of different number listed in the first column (time) and how many times they occurs (b).
[time,b] = unique(M(:,1));
b = [b; length(M)];
How can I continue it?
Thanks in advance.

Réponse acceptée

Stephen23
Stephen23 le 19 Avr 2022
M = [[0;0.2;0.2;0.4;0.6;0.6;0.6],rand(7,3)]
M = 7×4
0 0.4950 0.3418 0.1799 0.2000 0.7419 0.8047 0.6176 0.2000 0.0316 0.7905 0.7259 0.4000 0.0520 0.9471 0.8603 0.6000 0.2431 0.9200 0.8624 0.6000 0.2946 0.9786 0.6720 0.6000 0.1605 0.0039 0.7209
D = diff(find([1;diff(M(:,1));1]));
C = mat2cell(M,D,4)
C = 4×1 cell array
{[ 0 0.4950 0.3418 0.1799]} {2×4 double } {[0.4000 0.0520 0.9471 0.8603]} {3×4 double }
C{:}
ans = 1×4
0 0.4950 0.3418 0.1799
ans = 2×4
0.2000 0.7419 0.8047 0.6176 0.2000 0.0316 0.7905 0.7259
ans = 1×4
0.4000 0.0520 0.9471 0.8603
ans = 3×4
0.6000 0.2431 0.9200 0.8624 0.6000 0.2946 0.9786 0.6720 0.6000 0.1605 0.0039 0.7209
  3 commentaires
Fabio Taccaliti
Fabio Taccaliti le 19 Avr 2022
Modifié(e) : Fabio Taccaliti le 19 Avr 2022
What about if I want to plot each last 3 columns of the sub-arrays? column 2 is the x-cooediante, column 3 the y and column 4 the z.
figure(1)
for i = length(C)
hold on; grid on; grid minor; axis equal;
scatter3(C{i}(:,2),C{i}(:,3),C{i}(:,4))
view(3)
xlabel('x [mm]')
ylabel('y [mm]')
zlabel('z [mm]')
end
Something like this, but this plot just the first one

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