mean according to another column

3 vues (au cours des 30 derniers jours)
Thar
Thar le 16 Jan 2015
Commenté : Thar le 16 Jan 2015
Hi all!! I need your help please!
My data are in 4 columns:
5,11550634065452 5,68000000000000 2,89500000000000e+18 0,000277777777777821
5,11371667045788 5,68027777777778 4,28850000000000e+18 0,000277777777778709
5,11237469650691 5,68055555555556 3,99960000000000e+18 0,000277777777776933
5,11058681295688 5,68083333333333 3,56330000000000e+18 0,000277777777777821
4,22865065482816 5,89750000000000 2,74900000000000e+18 0,216666666666667
4,22683293766465 5,89805555555556 3,82680000000000e+18 0,000555555555555642
4,22531743417035 5,89861111111111 3,05860000000000e+18 0,000555555555555642
4,22380486438042 5,89916666666667 3,72440000000000e+18 0,000555555555555642
4,22229371155370 5,89944444444445 3,42520000000000e+18 0,277777777777821
4,22078125510264 5,90000000000000 2,90090000000000e+18 0,000555555555555642
4,21927232883456 5,90027777777778 2,72760000000000e+18 0,000277777777776933
4,21806586681390 5,90083333333333 3,59180000000000e+18 0,000555555555555642
4,21655652713407 5,90138888888889 4,65340000000000e+18 0,000555555555555642
I'd like to find mean values from columns 1:3, but not from all lines. The 4th column has some lines where the number is >0.01, like the lines 5 & 9. So, I want to find the mean from lines 1-4, 5-8, and 9 until the number from 4th column is >0.01 and so on, until line 4878. (the step is not stable).
What can i do?
Thank you!

Réponses (1)

Azzi Abdelmalek
Azzi Abdelmalek le 16 Jan 2015
If your matrix is named a
idx=a(:,4)<=0.01
out=mean(a(idx,1:3),2)
  2 commentaires
Thar
Thar le 16 Jan 2015
The result out has more lines from the first data. It not find mean values from lines 1:4 then 5:8 and so on. Can i do anything else?
Thank you!
Thar
Thar le 16 Jan 2015
my script is:
G=[X,X1,Y]; %airmass, time, SCD
for k=1:4828
G(k+1,4)=G(k+1,2)-G(k,2); %dif_time
end
idx=G(:,4)<=0.01;
out=mean(G(idx,1:3),2);

Connectez-vous pour commenter.

Catégories

En savoir plus sur Logical dans Help Center et File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by