access elements of vector within struct

3 vues (au cours des 30 derniers jours)
dleal
dleal le 22 Avr 2022
Modifié(e) : Matt J le 22 Avr 2022
Hi all,
I want to update the values of a vector, within a struct, recursively, in a for loop. In particular, I am receiving real time inputs(yobs, observations in milliseconds for several hours), for different objects, which I am storing within a struct (S, for example) :
yobs = randn(1,100); %vector of observations, which i am receiving one by one
S = struct;
S.A = nan(1,100); %preallocate for speed
for ii = 1:numel(yobs)
temp = S.A;
temp(ii) = yobs(ii);
S.A = temp;
end
Accessing the struct in this way, requires a copy of S.A into temp, which will be slow since the iterations will be over millions of observations.
Alternatively, I could not preallocate S.A, but that will also consume time. Is it absolutely necessary to copy the previous values of S.A into a temporary variable as above? thank you

Réponse acceptée

Voss
Voss le 22 Avr 2022
"Is it absolutely necessary to copy the previous values of S.A into a temporary variable as above?"
No, it's not necessary.
yobs = randn(1,100); %vector of observations, which i am receiving one by one
S = struct;
S.A = nan(1,100); %preallocate for speed
for ii = 1:numel(yobs)
S.A(ii) = yobs(ii);
end
  1 commentaire
dleal
dleal le 22 Avr 2022
thank you _ ... for some reason I thought S.A(ii) would produce a struct array. I keep confusing S(ii).A and S.A(ii)... thank you!

Connectez-vous pour commenter.

Plus de réponses (1)

Matt J
Matt J le 22 Avr 2022
Modifié(e) : Matt J le 22 Avr 2022
S.A doesn't appear to be playing any role within your loop at all. You could just as easily have done,
temp = nan(1,100); %preallocate for speed
for ii = 1:numel(yobs)
temp(ii) = yobs(ii);
end
S.A = temp;

Catégories

En savoir plus sur Logical dans Help Center et File Exchange

Tags

Produits


Version

R2022a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by