Best fitting curve for variable data
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Hello
I was trying fitting to fit the following data
x = 1.0779 1.2727 1.4700 1.5766 1.6471 1.7396 1.7828 1.8208 1.8370
y = 7.9511 9.8400 12.8838 15.1925 31.0055 36.0292 62.5528 87.9648 176.4142
for the equation:
y = a exp(b*(1/x)^c)
where a ba nd c are fitting paramters.
I triesd the fiting but unfortinately i was not able to magae it. It will be really helpful experties can guide me in this context.
Thanks in advance!
0 commentaires
Réponse acceptée
Matt J
le 23 Avr 2022
Modifié(e) : Matt J
le 23 Avr 2022
Using fminspleas from the File Exchange
% data
x = [1.0779 1.2727 1.4700 1.5766 1.6471 1.7396 1.7828 1.8208 1.8370]' ;
y = [7.9511 9.8400 12.8838 15.1925 31.0055 36.0292 62.5528 87.9648 176.4142]' ; ;
funlist={1,@(c,xx) (1./xx).^c};
[c,ab]= fminspleas(funlist,-3,x,log(y),-inf,0);
a=exp(ab(1));
b=ab(2);
a,b,c
xx=linspace(min(x),max(x),100);
fun=@(x)a*exp(b*(1./x).^c);
plot(x,y,'o',xx,fun(xx))
ylim([0,max(y)])
0 commentaires
Plus de réponses (1)
KSSV
le 23 Avr 2022
Modifié(e) : KSSV
le 23 Avr 2022
% data
x = [1.0779 1.2727 1.4700 1.5766 1.6471 1.7396 1.7828 1.8208 1.8370]' ;
y = [7.9511 9.8400 12.8838 15.1925 31.0055 36.0292 62.5528 87.9648 176.4142]' ; ;
eqn = @(a,b,c,x) a*exp(b*(1./x).^c) ; % equation to fit
% Define Start points
x0 = [1 1 1];
% fit-function
fitfun = fittype(eqn);
% fit curve
[fitted_curve,gof] = fit(x,y,fitfun,'StartPoint',x0)
% Save the coeffiecient values for a,b,c
coeffvals = coeffvalues(fitted_curve);
% Plot results
scatter(x, y, 'bs')
hold on
plot(x,fitted_curve(x),'r')
legend('data','fitted curve')
3 commentaires
Voir également
Catégories
En savoir plus sur Spline Postprocessing dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!