Effacer les filtres
Effacer les filtres

Extracting an extra Matrix from ode45 solver

1 vue (au cours des 30 derniers jours)
David Togonidze
David Togonidze le 26 Avr 2022
Commenté : David Togonidze le 26 Avr 2022
Hey guys, I want to extract an extra matrix (eta_d) from the solver, which will contain values calculated at each time step.. Is there anyway I can do that? Thanks in advance for help.
Here is the function and executive file:
function dydt = ODEsystem(t,y)
phi=sin(t);
eta_d=cos(phi/2);
a=[1/sqrt(3);1/sqrt(3);1/sqrt(3)];
epsilon_d=a*sin(phi/2);
w_d=cos(t)*a;
w_d_skew=[0 -w_d(3,1) w_d(2,1);w_d(3,1) 0 -w_d(1,1);-w_d(2,1) w_d(1,1) 0];
K_p=[30 0 0;0 30 0;0 0 30];
K_d=[45 0 0;0 45 0;0 0 45];
I=[25000 0 0;0 100000 0;0 0 110000];
Iomega_d_dot=I*(-sin(t)*a);
omegacross_dIsame=w_d_skew*I*w_d;
dydt = zeros(7,1);
dydt(1) = (Iomega_d_dot(1,1)+ omegacross_dIsame(1,1)-K_p(1,1)*(eta_d*y(5)+y(6)*epsilon_d(3,1)-epsilon_d(2,1)*y(7)-y(4)*epsilon_d(1,1))-K_d(1,1)*(y(1)-w_d(1,1))+I(2,2)*y(2)*y(3)-I(3,3)*y(2)*y(3))/I(1,1);
dydt(2) = (Iomega_d_dot(2,1)+ omegacross_dIsame(2,1)-K_p(2,2)*(eta_d*y(6)-y(5)*epsilon_d(3,1)+epsilon_d(1,1)*y(7)-y(4)*epsilon_d(2,1))-K_d(2,2)*(y(2)-w_d(2,1))-I(1,1)*y(1)*y(3)+I(3,3)*y(3)*y(1))/I(2,2);
dydt(3) = (Iomega_d_dot(3,1)+ omegacross_dIsame(3,1)-K_p(3,3)*(eta_d*y(7)-y(6)*epsilon_d(1,1)+epsilon_d(2,1)*y(5)-y(4)*epsilon_d(3,1))-K_d(3,3)*(y(3)-w_d(3,1))-I(2,2)*y(2)*y(1)+I(1,1)*y(2)*y(1))/I(3,3);
dydt(4) = -0.5*(y(1)*y(5)+y(2)*y(6)+y(3)*y(7));
dydt(5) = -0.5*(y(2)*y(7)-y(3)*y(6)-y(4)*y(1));
dydt(6) = -0.5*(y(3)*y(5)-y(1)*y(7)-y(4)*y(2));
dydt(7) = -0.5*(y(1)*y(6)-y(2)*y(5)-y(4)*y(3));
end
y0 = [0.1;0.3;0.1;1;0;0;0];
tspan = [0 20];
[t,y] = ode45(@ODEsystem,tspan,y0);

Réponse acceptée

Torsten
Torsten le 26 Avr 2022
y0 = [0.1;0.3;0.1;1;0;0;0];
tspan = [0 20];
[t,y] = ode45(@ODEsystem,tspan,y0);
eta_d = cos(sin(t)/2);
Extracted.
  1 commentaire
David Togonidze
David Togonidze le 26 Avr 2022
I was trying something similiar but getting the results that were not what i expected. But now I know that it is most likely bug in my code. Thank you for the help.

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Programming dans Help Center et File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by