Write a program so that with help of 3 for-end loops we form a matrix C that will be equivalent to C= A*B - B*A
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Let 2 matrices (A and B) be given in MatLab.Write a program so that with help of 3 for-end loops we form a matrix C that will be equivalent to C= A*B - B*A
3 commentaires
Bruno Luong
le 29 Avr 2022
@Jakub Devera matrix is 2D, and naive multipling two matrices requires 3 nested loops.
Jan
le 29 Avr 2022
Modifié(e) : Jan
le 29 Avr 2022
This is a homework question. As usual, post, what you have tried so far and ask a specific question concern the remaining Matlab problem.
The actual problem is interesting. You can avoid to calculate A*B and B*A explicitly.
@Jakub Devera: If A*B and B*A is mathematically defined, A and B must be square matrices.
Réponses (2)
Srija Kethiri
le 2 Mai 2022
Hi Iva,
From my understanding you want to to get a matrix C, where C = A*B - B*A. To get the matrix C it is possible only if A and B both are square matrices with same dimension.
The code for finding C is:
[c,d] = size(A);
[e,f] = size(B);
C = zeros(c,c);
if(c==d && e==f && c==e)
for i=1:c
for j=1:c
sum1 =0;
sum2 =0;
for p = 1:c
sum1 = sum1 + A(i,p)*B(p,j);
sum2 = sum2 +B(i,p)*A(p,j);
C(i,j) = sum1-sum2;
end
end
end
end
2 commentaires
John D'Errico
le 2 Mai 2022
Please don't answer obvious homework assignment questions, when no effort was made or shown. This does not help the student. It only teaches them to post the rest of their homework on Answers, and that hurts the site.
Jan
le 2 Mai 2022
I agree with John.
Your code overwrites C(i,j) in each iteration of the inner loop. One variable would be enough for the accumulation.
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