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Looping with unequal increment

4 vues (au cours des 30 derniers jours)
Utsav
Utsav le 21 Jan 2015
Commenté : John D'Errico le 21 Jan 2015
I have x= 5,15,25,30,45,60,65,70,75,90
other parameters (in the body of loop) depends on x values above
I have to run a loop
for i=min(x) : B :max(x)
Body
endfor
What shall be the B? How to go about it?
  1 commentaire
Stephen23
Stephen23 le 21 Jan 2015
Note that you should not use i or j for your loop variable names, as these are the names of the inbuilt imaginary unit .

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Roger Stafford
Roger Stafford le 21 Jan 2015
Modifié(e) : Roger Stafford le 21 Jan 2015
x = [5,15,25,30,45,60,65,70,75,90];
for i = 1:length(x)
% Get parameter values from x(i) and store them at i-th array positions
end
  4 commentaires
Roger Stafford
Roger Stafford le 21 Jan 2015
Good point, Stephen. I carelessly used 'i' here just because "i-th" is easier to pronounce than, say, "ix-th".
John D'Errico
John D'Errico le 21 Jan 2015
I'll admit, I like i as a loop variable. It is a throwback to my Fortran days, when i was the variable of choice for loops.

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