# Storing values in a matrix out of nested for loops

2 vues (au cours des 30 derniers jours)
SM le 30 Avr 2022
Commenté : SM le 3 Mai 2022
I am trying to write a code where I want to store the values out of element wise multiplication using three for loops. I tried a lot but it only shows values for a particular iteration. Each number in the matrices have to be multiplied with every other number of the other two matrices and the results to be stored in one row or column matrix. Kindly help.
m1=[0.5; 0.5];
m2=[0.6; 0.4];
m3=[0.2; 0.8];
m=[m1 m2 m3];
s1=m(:,1);
s2=m(:,2);
s3=m(:,3);
s5=zeros(1,8);
for i=1:length(s1)
for j=1:length(s2)
for k=1:length(s3)
s4=s1(i).*s2(j).*s3(k);
end
end
end
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### Réponse acceptée

Akira Agata le 30 Avr 2022
m1 = [0.5; 0.5];
m2 = [0.6; 0.4];
m3 = [0.2; 0.8];
[q, p, r] = meshgrid(m2, m1, m3);
s4 = p.*q.*r;
disp(s4)
(:,:,1) = 0.0600 0.0400 0.0600 0.0400 (:,:,2) = 0.2400 0.1600 0.2400 0.1600
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Akira Agata le 2 Mai 2022
But I'm not sure why "0.8" appears twice in your s5 (3rd and 8th elements)
m1 = [0.5; 0.5];
m2 = [0.6; 0.4];
m3 = [0.2; 0.8];
[q,r, p] = meshgrid(m2, m3, m1);
s = p.*q.*r;
s = s(:);
disp(s)
0.0600 0.2400 0.0400 0.1600 0.0600 0.2400 0.0400 0.1600
SM le 3 Mai 2022
Thanks a lot! This works fine.

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