Storing values in a matrix out of nested for loops

I am trying to write a code where I want to store the values out of element wise multiplication using three for loops. I tried a lot but it only shows values for a particular iteration. Each number in the matrices have to be multiplied with every other number of the other two matrices and the results to be stored in one row or column matrix. Kindly help.

m1=[0.5; 0.5];
m2=[0.6; 0.4];
m3=[0.2; 0.8];
m=[m1 m2 m3];
s1=m(:,1);
  s2=m(:,2);
  s3=m(:,3);
   s5=zeros(1,8);
  for i=1:length(s1)
      for j=1:length(s2)
           for k=1:length(s3)
  s4=s1(i).*s2(j).*s3(k);

      end
  end
    
  end

Answer 1

[Akira Agata]

how about the following?

m1 = [0.5; 0.5];
m2 = [0.6; 0.4];
m3 = [0.2; 0.8];
[q, p, r] = meshgrid(m2, m1, m3);
s4 = p.*q.*r;
disp(s4)

(:,:,1) =

    0.0600    0.0400
    0.0600    0.0400


(:,:,2) =

    0.2400    0.1600
    0.2400    0.1600

[SM]

Actually I want my answer to be s5=[0.5*0.6*0.2; 0.5*0.6*0.8; 0.8; 0.5*0.4*0.2; 0.5*0.4*0.8; 0.5*0.6*0.2; 0.5*0.6;0.8; 0.5*0.4*0.2; 0.5*0.4*0.8]. A single column matrix/row matrix

s5=0.0600

0.2400

0.8000

0.0400

0.1600

0.0600

0.3000

0.8000

0.0400

0.1600

[Akira Agata]

Please modify slightly, like below:

But I'm not sure why "0.8" appears twice in your s5 (3rd and 8th elements)

m1 = [0.5; 0.5];
m2 = [0.6; 0.4];
m3 = [0.2; 0.8];

[q,r, p] = meshgrid(m2, m3, m1);
s = p.*q.*r;
s = s(:);

disp(s)

    0.0600
    0.2400
    0.0400
    0.1600
    0.0600
    0.2400
    0.0400
    0.1600

[SM]

Thanks a lot! This works fine.