How can i get all paths between two nodes ??
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shaifali shakya
le 23 Jan 2015
Commenté : Image Analyst
le 21 Juin 2020
How can i get all paths between two nodes
2 commentaires
Geoff Hayes
le 24 Jan 2015
Shaifali - you will need to provide some more details. Do you have a matrix representing all paths between a set of nodes and you wish to find all paths between just two of them?
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Kelly Kearney
le 24 Jan 2015
If you're looking for the shortest paths, there are a few FEX entries that implement algorithms for this, including both depth-first and breadth-first searches. I use matlab_bgl, which includes several shortest path algorithms.
However, if you're really looking for all paths between two nodes, I found that algorithms for that are more scarce. I wrote pathbetweennodes.m to do just that... I wrote it for fairly small graphs (~50 nodes or fewer), so I'm not sure how efficient it might be for larger graphs, but it has worked well for my purposes.
2 commentaires
Kelly Kearney
le 1 Sep 2016
An update on my answer, since this is now out of date...
Also, Matlab 2015b and above now includes some native shortest path methods for graph objects, so you don't need matlab_bgl.
Pham Minh Cong
le 9 Mar 2020
Great work !
Thank you for your contribution.
I am new to this subject, do you have a name for your algorithms ?
Plus de réponses (2)
Emad NB
le 14 Déc 2018
You can use my function below. I use weight factor as a signal to find different pathes:
function pth=pathof(graph,startn,endn)
stop=0;
n=0;
while stop~=1
n=n+1;
Temp=shortestpath(graph,startn,endn);
eidx=findedge(graph,Temp(1:end-1),Temp(2:end));
if n~=1
if length(Temp)==length(pth{n-1,1})
if Temp==pth{n-1,1}
stop=1;
else
pth{n,1}=Temp;
graph.Edges.Weight(eidx)=100;
end
else
pth{n,1}=Temp;
graph.Edges.Weight(eidx)=100;
end
else
pth{n,1}=Temp;
graph.Edges.Weight(eidx)=100;
end
clear Temp eidx;
end
2 commentaires
mujahid razman
le 21 Juin 2020
Simulate any shortest path algorithm between point A to point B if the map is known. Consider the map consists of free space and any configuration of finite obstacles. The result can be shown in 2-D graph where 0 means obstacle, 1 means free space and 2 means trajectory followed. For instance you can simulate A* algorithm in Matlab.
how to solve please help
Image Analyst
le 21 Juin 2020
Why not use bwdistgeodesic()? Your problem statement is exactly what Steve worked on. Did you overlook my answer with the link to his blog?
The above image is from part 5 of his blog series. Don't you think that pretty much describes your problem?
Image Analyst
le 24 Jan 2015
See Steve's blog series on this: http://blogs.mathworks.com/steve/2011/11/01/exploring-shortest-paths-part-1/
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