storing data from while loop

Hello, I'm trying to sort the data from vector AA such that if AA(n+1) > AA(n) it'll store the indices into a matrix {data} if theres a break, (AA(N+1) < A(n)) data in AA will occupy a new column

This is the code I got for so far, however the {data} matrix is empty

AA = [ 1 2 3 5 7 10 9 11 13 14 17 19 17 22 25];

data = {};

k =1;

while true

    idx = find (AA < AA - 1, 1);
    if ~isempty (idx);
        data{k} = AA(1:idx-1);
        AA = AA(idx:end);
        k = k + 1;
    else
        data {k} = AA(1:end);
        break
    end
end

The final result should be the matrix {data} contains the following

cell 1x1: [1 2 3 5 7 10]

cell 1x2: [11 13 14 17 19]

cell 1x3: [22 25]

Thanks!

Answer 1

[Guillaume]

Assuming you made a typo and cell{3} should be [17 22 25]:

AA = [ 1 2 3 5 7 10 9 11 13 14 17 19 17 22 25];
data = mat2cell(AA, 1, diff([0 find(diff(AA) < 0) numel(AA)]))

Basically, find the length of the runs, using diff and find and use mat2cell to convert to cell.