Random exponential function between two values

5 vues (au cours des 30 derniers jours)
Nicola De Noni
Nicola De Noni le 18 Mai 2022
Commenté : Sam Chak le 18 Mai 2022
Hello everyone! I’m trying to create a random vector with a maximum value of xmax_out = 65 and a minimum value of xmin_out = 16. This vector. However, I would like this vector to have an exponential shape, as shown, because I want to simulate the temperature that decreases in contact with a hot fluid to be cooled.
As you can see: I would like the temperature at time 0 (therefore origin of the x axis) to be equal xmax_out while at time t the temperature reaches the xmin_out value. In the project the cooling time is about 50 min.
I tried to use the following code to generate a decreasing random vector, but unfortunately it is linear.
% Temperature range
n = 50; % Length of time [min]
xmin_out = 16 + 273.15; % Minimum outlet temperature [K]
xmax_out = 65 + 273.15; % Maximum outlet temperature [K]
% Random Vector of temperature:
T_out = sort((xmax_out-xmin_out)*rand(n,1)+xmin_out, "descend");
Thanks!

Réponse acceptée

Sam Chak
Sam Chak le 18 Mai 2022
Modifié(e) : Sam Chak le 18 Mai 2022
Are you looking for an exponential decay like this?
t = linspace(0, 3000, 30001);
tmin = 50;
xmin = 16;
xmax = 65;
k = -log(xmin/65)/(60*tmin);
T = xmax*exp(-k*t);
plot(t/60, T, 'linewidth', 1.5)
grid on
xlabel('Time, t [min]')
ylabel('Temperature, T')
  6 commentaires
Torsten
Torsten le 18 Mai 2022
Modifié(e) : Torsten le 18 Mai 2022
The shape comes from an exponential, but it's not visible in the interval [0:50].
If you plot for
t = linspace(0,3000*10,3000)
, you'll see the exponential behaviour.
Sam Chak
Sam Chak le 18 Mai 2022
Since the absolute Kelvin is just an additive reference, you can do this way:
t = linspace(0, 36000); % 3000 seconds == 50 min; plot up to 600 min
tmin = 50;
xmin = 20; % Temperature [Kelvin]
xmax = 45; % Temperature [Kelvin]
k = -log((xmin)/(xmax))/(60*tmin);
Temp = (xmax)*exp(-k*t) + 273.15;
plot(t/60, Temp, 'linewidth', 1.5)
grid on
xlabel('Time, t [min]')
ylabel('Temperature, T [K]')
It actually behaves exponentially. Just that the 50 min duration is relatively short to see the effect.

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