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WhatsApp can i do to plot the fonction below respect to the variables x and t

1 vue (au cours des 30 derniers jours)
When i run the code the following error apear
Index exceeds Matrix dimension

Réponse acceptée

Sam Chak
Sam Chak le 19 Mai 2022
Are you trying to plot something like this?
C = [];
X = linspace(0,1,25);
T = linspace(0,10,250);
for i = 1:length(X)
for j = 1:length(T)
C(i,j) = exp(-(1/2)*X(i))*((0.5e-3*exp(-182.4229*T(j))-0.24e-2*exp(-104.1124*T(j))+.4162*exp(-1.6659*T(j))-.1053*exp(-14.2761*T(j))+0.87e-2*exp(-48.3112*T(j)))*(.5449591281*cos(.4928312111*X(i))+1.492792677*sin(.4928312111*X(i))))...
+(-0.8e-3*exp(-182.4229*T(j))+0.22e-2*exp(-104.1124*T(j))-0.155e-1*exp(-1.6659*T(j))+.1858*exp(-14.2761*T(j))-0.239e-1*exp(-48.3112*T(j)))*(1.227596366*cos(3.450769558*X(i))+.4802566691*sin(3.450769558*X(i)))...
+(0.9e-3*exp(-182.4229*T(j))-0.101e-1*exp(-104.1124*T(j))+0.3e-3*exp(-1.6659*T(j))-0.133e-1*exp(-14.2761*T(j))+0.596e-1*exp(-48.3112*T(j)))*(1.370614035*cos(6.412844*X(i))+.2885348446*sin(6.412844*X(i)))...
+(-0.47e-2*exp(-182.4229*T(j))+0.272e-1*exp(-104.1124*T(j))-0.3e-3*exp(-1.6659*T(j))+0.7e-3*exp(-14.2761*T(j))-0.44e-2*exp(-48.3112*T(j)))*(1.384197996*cos(9.546645839*X(i))+.1957407164*sin(9.546645839*X(i)))...
+(0.123e-1*exp(-182.4229*T(j))-0.18e-2*exp(-104.1124*T(j))-0.7e-3*exp(-14.2761*T(j))+0.4e-3*exp(-48.3112*T(j)))*(1.396843135*cos(12.65883563*X(i))+.1489661678*sin(12.65883563*X(i)));
end
end
plot(X, C(:,22), 'bo', X, C(:,32), 'mo', X, C(:,42), 'co', X, C(:,53), 'go', X, C(:,63), 'ro')

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