How to define variable (for later use) that contains another defined variables

Simple question

I.e I have variable N=Np/Ns. I;ve defined values for Np and Ns (which I may want to change later) but for my latter euqations I want to put simply only N, insteed of typing Np/Ns. How to define N in that way when I pun N in some equation it will pass Np/Ns.

I've tried simply N = 'Np/Ns' , but when I checked it by typing F = N + 1, insteed of simply calculate F = Np/Ns + 1, the output is strange 8 element matix.

[Stephen23]

"the output is strange 8 element matix"

Not very strange: you created a character vector and then added one to every character code:

1+'Np/Ns'

ans = 1×5

79 113 48 79 116

If you want to perform numeric/symbolic operations, character vectors are unlikely to be the solution.

Answer 1

[David Hill]

np=5;ns=3;
n=@(np,ns)np/ns;
f=n(np,ns)+1;
np=8;ns=5;
f=n(np,ns)^2+3;

[Marcin Fisior]

Thanks but I dont want to type everywhere n(np,ns). since I need to use it in vary large equations (where N is only one of many of similar variables) so this method will be prone to errors. Is there possibility to to type only "N" ? (should be since Np/Ns is already assigned with values to N)

and the first equation when I have to put N are those 2 (later the quations are making more complicated since they are nested)

where Vcr

[Torsten]

What variables are given ? What variables are unknown ? What is the final task of your computations ?

[Marcin Fisior]

Torsten starting from page 5. IV. DESIGN ALGORITHM DERIVATION (PN MODE)

Np,Ns, Vi,min, fs,min are given, Cr is iterated to get Lr, Lp and wr

https://www.ece.queensu.ca/people/Y-F-Liu/Pub/Papers/2016/2016_TPEL_Zhiyuan_An%20Accurate%20Design%20Algorithm%20for%20LLC%20Resonant%20Converters-Part%20I.pdf

[Stephen23]

Why not just write a function? That seems like the obvious approach.

[Torsten]

As Stephen says, put all your computations - one after the other - in a function. Then you don't need to combine function handles, but you can simply work with variables.

[Marcin Fisior]

Yeah, now I see that will be best approach. Thanks