Extract sub array from d-dimensional array given indices for each dimension

13 vues (au cours des 30 derniers jours)
Suppose I have a d-dimensional array A which is size d_1 by d_2 by....by d_d and for each dimension i have a index vector vd_i such that vd_i(1)>=1 and vd_i(end)<= size(A, i). How do I extract the sub array A(vd_1,vd_2,...,vd_3) when d is arbitrary?
Edit: as mentioned by the wonderful Matt J, I meant that 1<= vd_i(j)<= size(A,i) for all i,j.
  2 commentaires
Matt J
Matt J le 20 Mai 2022
Modifié(e) : Matt J le 21 Mai 2022
and for each dimension i have a index vector vd_i such that vd_i(1)>=1 and vd_i(end)<= size(A, i).
I think what you really mean is 1<= vd_i(j)<= size(A,i) for all i,j. If that's not what you meant then, well, you should check that it's true, because it's a requirement in any subscript indexing operation.

Connectez-vous pour commenter.

Réponse acceptée

Matt J
Matt J le 20 Mai 2022
Modifié(e) : Matt J le 20 Mai 2022
If you have your vd_i in a cell array V={vd_1,vd_2,...,vd_d}, you can do
A(V{:})

Plus de réponses (2)

Voss
Voss le 20 Mai 2022
% random 4-D (4x8x5x10) array A:
d_siz = [4 8 5 10];
A = randn(d_siz);
size(A)
ans = 1×4
4 8 5 10
% make the index vectors for each dimension
% into a cell array:
vd = {[2 3] [1 3 5 7] [2 3 4] 4:8};
% index into A in each dimension:
A_subs = A(vd{:});
size(A_subs)
ans = 1×4
2 4 3 5

dpb
dpb le 20 Mai 2022
Did you try the obvious???
Smallish example, but works in general...
>> d=3;A=reshape(1:4^d,4,4,[]) % make up a sample array to play with that can read
>> A
A(:,:,1) =
1 5 9 13
2 6 10 14
3 7 11 15
4 8 12 16
A(:,:,2) =
17 21 25 29
18 22 26 30
19 23 27 31
20 24 28 32
A(:,:,3) =
33 37 41 45
34 38 42 46
35 39 43 47
36 40 44 48
A(:,:,4) =
49 53 57 61
50 54 58 62
51 55 59 63
52 56 60 64
>>
>> v1=2:3;v2=v1;v3=v1; % pick middle two of each dimension
>> A(v1,v2,v3)
ans(:,:,1) =
22 26
23 27
ans(:,:,2) =
38 42
39 43
>>
is, by inspection, the array elements of 2nd, 3rd plane and the central four elements of each, respectively.

Catégories

En savoir plus sur Matrix Indexing dans Help Center et File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by