Is it possible to use the smooth function with a multidimensional matrix having NaN values?

4 vues (au cours des 30 derniers jours)
The NaN values would be the points where the smooth function generates the new values.
Hope this is clear. Thank you!

Réponses (1)

Sergio Yanez-Pagans
Sergio Yanez-Pagans le 23 Mai 2022
  1 commentaire
alberto tonizzo
alberto tonizzo le 23 Mai 2022
Thank you but I have a matrix with 5 dimensions...
Matrix dimensions must agree.
Error in smoothn>dctn (line 704)
y = y.*w{dim}(:,ones(1,n));
Error in smoothn>@(x)dctn(x) (line 632)
z = cellfun(@(x) dctn(x),z,'UniformOutput',0);
Error in smoothn>InitialGuess (line 632)
z = cellfun(@(x) dctn(x),z,'UniformOutput',0);
Error in smoothn (line 421)
z = InitialGuess(y,IsFinite);

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