How to remove the dublicated cells and empty cells

[A B]=size(SA);
for k=2:A
    for j=1:B
    if SA(k,j)~=0
         as=as+1;
        Atable{k,:}(:,as)=[SA(1,j) SA(k,j) SA(k,j)/(e-b+1) log10(SA(k,j)/(e-b+1))];
    end
       end
end

I have a 1X36 SA matrix and I obtained the values which are not equal to zero but there is an extra empty cell in Atable. How should I modify this code to remove the empty cell?

Also, In the double matrixes, there are some dublicated elements in each row but I want to remove them by keeping the last dublicated value. For example, If I have A matrix, I want to obtain the final A as shown in below.

A=[1 2 3 4 5 6 7 8;0.7 0.7 0.6 0.6 0.6 0.5 0.5 0.4]

Final_A=[2 5 7 8;0.7 0.6 0.5 0.4]

Answer 1

[KSSV]

Let A be your cell array.

 A = A(~cellfun('isempty',A)) ;  % A has no more empty cells 

[busra gogen]

thank you!

Answer 2

[Walter Roberson]

format long g
A = [1 2 3 4 5 6 7 8;0.7 0.7 0.6 0.6 0.6 0.5 0.5 0.4]

A = 2×8

1 2 3 4 5 6 7 8 0.7 0.7 0.6 0.6 0.6 0.5 0.5 0.4

[~, ia] = unique(fliplr(A(2,:)), 'stable');
fliplr(A(:,end-ia+1))

ans = 2×4

2 5 7 8 0.7 0.6 0.5 0.4

[busra gogen]

thank you! It works perfectly..