I am asked to write a function called standard_deviation_distance that takes as input a data vector [1xN] v and a number x [1x1], in that order. And I have code to call your function:
v = [10 12 14];
x = 7;
dist = standard_deviation_distance(v,x)% =-2.5

Réponses (3)

VBBV
VBBV le 5 Juin 2022
Modifié(e) : VBBV le 10 Nov 2022
v = [10 12 14];
x = ones(1,numel(v))*7;% length of x vector (weights) for each element and to be same as vector v
dist = standard_deviation_distance(v,x);
disp(['The standard deviation distance is ', num2str(dist)])
The standard deviation distance is 1.633
function y = standard_deviation_distance(v,x)
y = std(v,x);
end
Himanshu Desai
Himanshu Desai le 31 Mai 2023
Modifié(e) : Himanshu Desai le 31 Mai 2023
function y = standard_deviation_distance(v,x)
m = mean(v);
s = std(v);
y = (x-m)/s;
end
dist = -2.500
v = [10 12 14];
x = 7;
y = standard_deviation_distance(v,x)
Mark
Mark le 1 Août 2025
Modifié(e) : Walter Roberson le 1 Août 2025
v = [10 12 14];
x = ones(1, numel(v))*7;
dist = std(v,x)
dist = 1.6330
disp(['The standard deviation distance is ' num2str(dist)])
The standard deviation distance is 1.633

3 commentaires

Walter Roberson
Walter Roberson le 1 Août 2025
I corrected the nume1() call to be numel()
Torsten
Torsten le 1 Août 2025
Modifié(e) : Torsten le 1 Août 2025
I don't see a difference to @VBBV 's solution (except for "nume1" instead of "numel").
Maybe it was meant as "test test test".
Walter Roberson
Walter Roberson le 2 Août 2025
@VBBV solution involved a function (as was required by the terms of the question)

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