How to pad NaNs in a matrix having small size to make equivalent with matrix of large size?

Hi there,

Suppose I have given matrices A= [1 2 3; 4 5 6; 7 8 9] and B=[1 2; 3 4]. Now, I just wanted to pad NaNs in matrix B to make equal size to that of A. Your help will be greatly appreciated.

Thank you in advance.

Answer 1

[Voss]

A = [1 2 3; 4 5 6; 7 8 9];
B = [1 2; 3 4];

[ma,na] = size(A);
[mb,nb] = size(B);

% one way:
B_new = [B NaN(mb,na-nb); NaN(ma-mb,na)]

B_new = 3×3

1 2 NaN 3 4 NaN NaN NaN NaN

% another way:
B_new = NaN(ma,na);
B_new(1:mb,1:nb) = B

B_new = 3×3

1 2 NaN 3 4 NaN NaN NaN NaN

[Sushil Pokharel]

@Voss, thank you so much for your help. This is exactly what I wanted; I really appreciate your time and help.

[Voss]

You're welcome!

Answer 2

[Jan]

A = [1 2 3; 4 5 6; 7 8 9];
B = [1 2; 3 4];
C = padarray(B, max(0, size(A) - size(B)), NaN, 'post')

C = 3×3

1 2 NaN 3 4 NaN NaN NaN NaN