Workaround for the expinv function in statistics toolbox

Hi,

I have been working with the norminv function for a while using my own code as follow:

function z = norminv(p,sigma,mu)
    z = sigma.*(-sqrt(2)*erfcinv(2*p))+mu;
end

However, I would like now to use the expinv function but I don't have access to the statistics toolbox. I was wondering if there is a way to work around using that particular function ?

Thanks !

Answer 1

[Torsten]

p = 0.3;
mu = 1/4;
x = -mu.*log(1-p)

x = 0.0892

x2 = expinv(p,mu)

x2 = 0.0892

[Ciprien]

Works just fine ! Thanks a lot