how to use if-else for select transition matrix input

d = 1,2,5,10 will use tm = p_clear but d = 3,4,7 will use tm = p_partly and d = 6,8,9 will use tm = p_cloudy. what command that i should use? The below is code that i wrote but it has problem about transition matrix that used not match with day. pleas help me.

if d == 1 || d == 2 || d == 3 | d == 4 || d == 5 || d == 7 || d == 17;
  p = cdf_partly;
elseif d == 6 || d == 8 || d == 9 || d == 10;
  p = cdf_mostly;
end

Answer 1

[Julia]

Hi,

I do not completely understand your problem, but you can write your conditions with a switch-case statement:

function p = test2(y)

switch y
    case {1, 2, 5, 10};
        p=0;
    case {3, 4, 7};
        p=1;
    case {6, 8, 9};
        p=2;
    otherwise
        p=-1;
end
end

[Anuchit Wibun]

 Thank you for your answer, but i did same you done, it's not work or i have some mistake. Please suggest to me again. This is my script>>>

seq = size(day,1);
for  step = 1:seq;
   d = day(step,1);
   switch d
       case{1,2,3,4,5,7,17,18,20,21,23,24,29,31}; 
           p = cdf_partly;
       case{6,8,9,10,11,13,14,15,16,19,22,25,26,27,28,30};
           p = cdf_mostly;
       case{12};
           p = cdf_cloudy;
       otherwise;
           p = cdf_clear;
  end

[Julia]

What mistake do you have? At the moment you overwrite p in each loop iteration. I suggest that you use an array and write p(step).

[Anuchit Wibun]

sorry, please you show example that you said. I cannot understand. Thank you very much.

[Michael Haderlein]

What exactly do you need? If you get an error message, please let us know what the message is and in which line it occurs. I notice that your code misses an "end" to close the for loop. Is that the problem?

[Anuchit Wibun]

I have file in worksheet its name "day". In this file is array of number [1; 1; 1; 2; 2; 2; 3; 3; 3; 4; 4; 4....,10]. From my code, i define "d" is value that read from day file in each row. That mean d=1,d=1,d=1,d=2,d=2,d=2...] and i create loop if d==1, i will determine p = cdf_clear(cdf_clear is matrix 10*10) but d==2, i will determine p=cdf_parlty(it not same cdf_clear). The result that i want is

output file : @ day   1    >> 0.34 [value that was got from *cdf_clear* (i,j)]
                            1    >> 0.85 [value that was got from *cdf_clear* (i,j)]
                            ...... 
                            2    >> 0.23 [value that was got from *cdf_partly* (i,j)]
                            .....
                               3    >> 0.26 [value that was got from *cdf_mostสั* (i,j)]

Are you understand with i explain?. I used if-else

if d==1 || d==3 || d==7;
   p = cdf_clear;
 elseif d==4 || d== 5;
   p = cdf_partly;
  end.

It not work. I'm beginner, i try to watch technique from internet but i don't know keyword for thing that i want. Thank you every much.

[Michael Haderlein]

Ok, but what is the problem with Julia's answer? If you replace p=0 with p=cdf_clear and so on, it should work.