Partial Differentiation of a function with exponential is different from other calculators

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Eric Chen
Eric Chen on 3 Jul 2022
Answered: Dyuman Joshi on 3 Jul 2022
function being tested:
exp[-0.5((h-c)/s)^2]
first differentiation with respect to 'h' in matlab code as follows:
syms x c h s
fn1 = exp(-0.5 * (((h-c)/s)^2));
diff(fn1,h)
ans = 
I got the answer = (exp(-(c - h)^2/(2*s^2))*(2*c - 2*h))/(2*s^2)
but in other calculators I got the answer =
Is there any thing wrong with my code?

Accepted Answer

Dyuman Joshi
Dyuman Joshi on 3 Jul 2022
There's nothing wrong with your answer, it's just simplified version of it. 2 from numerator and denominator is cancelled out and 1/2 is converted to 0.5 in the exponential.

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