taylor function is not working
Afficher commentaires plus anciens
i have matlab 2014b and when i came to get taylor expansion of some functions by writting taylor(sin(x),5,0) the matlab gives error knowing that all other functions works properly thanks in advance
Réponses (2)
Star Strider
le 5 Fév 2015
If you want to do a 5th-order Taylor series around an expansion point of 0 in R2014b, this works:
syms x
TSsin5 = taylor(sin(x), x, 'ExpansionPoint',0, 'Order',5)
and produces:
TSsin5 =
- x^3/6 + x
James Tursa
le 5 Fév 2015
Modifié(e) : James Tursa
le 5 Fév 2015
It is complaining about the 5 and 0 arguments, which don't match the expected syntax for calling the taylor function. Is something like this what you are trying to do?
>> syms x
>> taylor(sin(x))
ans =
x^5/120 - x^3/6 + x
>> taylor(sin(x),'Order',10)
ans =
x^9/362880 - x^7/5040 + x^5/120 - x^3/6 + x
Catégories
En savoir plus sur Calculus dans Centre d'aide et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!