Looking for where line intersects on itself
6 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Caitlin Bemis
le 13 Juil 2022
Modifié(e) : Bruno Luong
le 18 Juil 2022
I am looking to see where a line that is plotted by x and y intersects on itself. I have tried using unique() with the index given to see where the same combination of x and y occur, but based on the data that index did not make sense. I have also tried linexline() which was for two lines intersecting not a line intersecting itself. I have also tried to just zoom in on the graph and find the point. Although the amount of detail required for that was not working on my graph.
4 commentaires
Star Strider
le 15 Juil 2022
This answer was posted while I was sleeping, and since I cannot improve on it, I deleted my answer.
Réponse acceptée
Bruno Luong
le 15 Juil 2022
Modifié(e) : Bruno Luong
le 17 Juil 2022
If you interpolate your data by line segments it cross it selft at least 135 times
data = readtable('data.csv');
xy=table2array(data)';
X=polyselfx(xy);
fprintf('Number of intersections = %d\n', size(X,2))
figure
plot(xy(1,:),xy(2,:))
hold on
plot(X(1,:),X(2,:),'rx')
function X = polyselfx(P)
% Empty buffer
X = zeros(2,0);
filled = 0;
sizec = 0;
for n=2:size(P,2)-1
cn = seg2poly(P(:,n:n+1), P(:,1:n-1));
m = size(cn,2);
filled = filled+m;
% Buffer too small
if sizec < filled
sizec = max(filled, 2*sizec);
X(2,sizec) = 0;
end
% Store the result
X(:,filled+(-m+1:0)) = cn;
end
% remove the tails
X(:,filled+1:end) = [];
end % polyselfx
%%
function [cross_X, cross_t1, cross_t2, cross_i2] = seg2poly(s1, P)
a = s1(:,1);
M = P-a;
b = s1(:,2)-a;
nb2 = b(1)^2+b(2)^2;
% Check if the points are on the left/right side
x = [b(2) -b(1)]*M; % 1 x n
sx = sign(x);
% x -coordinates has opposite signs
crossx = sx(1:end-1).*sx(2:end) <= 0;
ix = find(crossx);
% cross point to the y-axis (along the segment)
x1 = x(ix);
x2 = x(ix+1);
d = b.'/nb2;
y1 = d*M(:,ix);
y2 = d*M(:,ix+1);
dx = x2-x1;
t1 = (y1.*x2-y2.*x1)./dx;
% Check if the cross point is inside the segment
ind = t1>0 & t1<=1;
if any(ind)
cross_t1 = t1(ind);
cross_t2= -x1(ind)./dx(ind);
cross_X = a + b*cross_t1;
cross_i2 = ix(ind);
else
cross_X = zeros(2,0);
cross_t1 = zeros(1,0);
cross_t2 = zeros(1,0);
cross_i2 = [];
end
end % seg2poly
5 commentaires
Bruno Luong
le 18 Juil 2022
Modifié(e) : Bruno Luong
le 18 Juil 2022
Here we go I modify the code and you get in idx the (first) indexes of the line segments and the fractional parametriec coordinates t of the intersections
data = readtable('data.csv');
xy=table2array(data)';
[X,idx,t]=polyselfx(xy);
fprintf('Number of intersections = %d\n', size(X,2))
figure
plot(xy(1,:),xy(2,:))
hold on
plot(X(1,:),X(2,:),'rx')
function [X, loc, t] = polyselfx(P)
% Crossing points polygons P
%
% INPUTS:
% P: two-row arrays, each column is a vertices
% OUTPUTS:
% X is two-row array, each column is an crossing point
% loc: two-row array, which edges the crossing point belong?
% first row corresponds to P1, second row to P2
% edge#1 is P(:,[1 2]), edge#2 is P(:,[2 3]), ... etc
% t: floating parametric of the crossing point
% Empty buffer
X = zeros(2,0);
loc = zeros(2,0);
t = zeros(2,0);
filled = 0;
sizec = 0;
for n=2:size(P,2)-1
[cn, t1, t2, i2] = seg2poly(P(:,n:n+1), P(:,1:n-1));
m = size(cn,2);
filled = filled+m;
% Buffer too small
if sizec < filled
sizec = max(filled, 2*sizec);
X(2,sizec) = 0;
loc(2,sizec) = 0;
t(2,sizec) = 0;
end
% Store the result
ifill = filled+(-m+1:0);
X(:,ifill) = cn;
loc(1,ifill) = n;
loc(2,ifill) = i2;
t(1,ifill) = t1;
t(2,ifill) = t2;
end
% remove the tails
X(:,filled+1:end) = [];
loc(:,filled+1:end) = [];
t(:,filled+1:end) = [];
end % polyselfx
%%
function [cross_X, cross_t1, cross_t2, cross_i2] = seg2poly(s1, P)
a = s1(:,1);
M = P-a;
b = s1(:,2)-a;
nb2 = b(1)^2+b(2)^2;
% Check if the points are on the left/right side
x = [b(2) -b(1)]*M; % 1 x n
sx = sign(x);
% x -coordinates has opposite signs
crossx = sx(1:end-1).*sx(2:end) <= 0;
ix = find(crossx);
% cross point to the y-axis (along the segment)
x1 = x(ix);
x2 = x(ix+1);
d = b.'/nb2;
y1 = d*M(:,ix);
y2 = d*M(:,ix+1);
dx = x2-x1;
t1 = (y1.*x2-y2.*x1)./dx;
% Check if the cross point is inside the segment
ind = t1>0 & t1<=1;
if any(ind)
cross_t1 = t1(ind);
cross_t2= -x1(ind)./dx(ind);
cross_X = bsxfun(@plus, a, b*cross_t1);
cross_i2 = ix(ind);
else
cross_X = zeros(2,0);
cross_t1 = zeros(1,0);
cross_t2 = zeros(1,0);
cross_i2 = [];
end
end % seg2poly
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Matrix Indexing dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!