cannot assign values to a cell during a parfor loop

I'm trying to evaluate the output of a high number of url in my domain, but I cannot deal with the "parfor" loop rules.
I get the following error:
Error: Unable to classify the variable 'checklist' in the body of the parfor-loop. For more information, see Parallel for Loops in MATLAB, "Solve Variable Classification Issues in parfor-Loops".
fold_list = cellstr(strcat('Folder_',num2str((100:125).','%#4.d')));
user_lists = cellstr(strcat('User_',num2str((1:100).','%#6.d')));
base_url = 'https://mydomain.com';
n_folds = length(fold_list);
n_users = length(user_lists);
checklist = cell(n_users+1,n_folds+1);
checklist(2:end,1) = user_lists;
checklist(1,2:end) = fold_list;
parfor j=1:n_users
for k=1:n_folds
try
checklist{j+1,k+1} = webread([base_url '/' fold_list{k} '/' user_lists{j} '.txt']);
catch
checklist{j+1,k+1} = 'N/A';
end
end
end
Error: Unable to classify the variable 'checklist' in the body of the parfor-loop. For more information, see Parallel for Loops in MATLAB, "Solve Variable Classification Issues in parfor-Loops".

 Réponse acceptée

Jan
Jan le 15 Juil 2022
Modifié(e) : Jan le 15 Juil 2022
Try this:
fold_list = cellstr(strcat('Folder_',num2str((100:125).','%#4.d')));
% By the way: Simpler:
% fold_list = sprintfc('folder_%03d', (100:125).'):
user_lists = cellstr(strcat('User_',num2str((1:100).','%#6.d')));
base_url = 'https://mydomain.com';
n_folds = length(fold_list);
n_users = length(user_lists);
checklist = cell(n_users+1,n_folds+1);
checklist(2:end,1) = user_lists;
checklist(1,2:end) = fold_list;
C = cell(n_users,n_folds)
parfor j=1:n_users
for k=1:n_folds
try
C{j,k} = webread([base_url '/' fold_list{k} '/' user_lists{j} '.txt']);
catch
C{j,k} = 'N/A';
end
end
end
cecklist(2:end, 2:end) = C;

5 commentaires

Thanks Jan!
I cannot just work with sprintfc function as Matlab cannot find it...
@endystrike: What a pity. This function was undocumented, but working since at leastr Matlab 5.3 . which Matlab version do you use?
version
ans = '9.12.0.2006483 (R2022a) Update 3'
sprintfc('%d', magic(3))
ans = 3×3 cell array
{'8'} {'1'} {'6'} {'3'} {'5'} {'7'} {'4'} {'9'} {'2'}
@JanI'm running R2022a, but there's no function called "sprintfc" unfortunately... :(
Bruno Luong
Bruno Luong le 17 Juil 2022
Modifié(e) : Bruno Luong le 17 Juil 2022
Humm it exists on mine
>> ver
-----------------------------------------------------------------------------------------------------
MATLAB Version: 9.12.0.1975300 (R2022a) Update 3
MATLAB License Number: xxxxxx
Operating System: Microsoft Windows 11 Home Version 10.0 (Build 22000)
Java Version: Java 1.8.0_202-b08 with Oracle Corporation Java HotSpot(TM) 64-Bit Server VM mixed mode
-----------------------------------------------------------------------------------------------------
MATLAB Version 9.12 (R2022a)
MATLAB Coder Version 5.4 (R2022a)
MATLAB Compiler Version 8.4 (R2022a)
Optimization Toolbox Version 9.3 (R2022a)
Parallel Computing Toolbox Version 7.6 (R2022a)
Signal Processing Toolbox Version 9.0 (R2022a)
>> sprintfc('%f', [1:3]) % yeah close your eyes master
ans =
1×3 cell array
{'1.000000'} {'2.000000'} {'3.000000'}
>> which sprintfc
built-in
>>
endystrike
endystrike le 17 Juil 2022
Modifié(e) : endystrike le 17 Juil 2022
@Bruno Luong thanks, I'll try reinstalling Matlab... Maybe something went wrong!
edit: I don't know how and why but now it seems to be working...
>> sprintfc('%04d', magic(3))
ans =
3×3 cell array
{'0008'} {'0001'} {'0006'}
{'0003'} {'0005'} {'0007'}
{'0004'} {'0009'} {'0002'}

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Loops and Conditional Statements dans Centre d'aide et File Exchange

Produits

Version

R2022a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by