Replacing elements in a vector

The values of an array match the index of elements in a vector. For example, the value of 5 in array1 below corresponds to whatever is in index 5 in vector1, i.e. the number 3 in this case. So how do I replace the value of the original number in array1 in the example by the number at the corresponding index in vector1? I realize this is a little confusing, so here's a mini example of what I want to do:

array1 = [1 2; 4 2; 5 5; 4 2];
vector1 = [2 1 1 4 3 4];
result = [2 1; 4 1; 3 3; 4 1];

Answer 1

[Paul]

array1 = [1 2; 4 2; 5 5; 4 2];
vector1 = [2 1 1 4 3 4];
result = [2 1; 4 1; 3 3; 4 1]

result = 4×2

2 1 4 1 3 3 4 1

result1 = vector1(array1)

result1 = 4×2

2 1 4 1 3 3 4 1

[L'O.G.]

@Paul Wow, I didn't know you could do that. Very cool! Could you explain how that works? I don't get it, but I'd like to understand if you don't mind.

[Paul]

vector1(array1) treats each entry of array1 as the linear index into vector1. The output takes the same shape as array1. It's the same as

array1 = [1 2; 4 2; 5 5; 4 2];
vector1 = [2 1 1 4 3 4];
reshape(vector1(array1(:)),size(array1))

ans = 4×2

2 1 4 1 3 3 4 1

[L'O.G.]

Thank you. That is really neat!

Answer 2

[DGM]

Your example isn't consistent. I'm assuming you want this:

A = [10 20; 30 40; 50 60];
idx = [2 1; 1 4; 3 3];

B = A.';
B = B(idx)

B = 3×2

20 10 10 40 30 30

[L'O.G.]

Thank you, but no, that's not what I want. I've edited my question to hopefully make it clearer.