Hello
I have many of array.
do you have any function for instead this CY.
CY = [cy(:,:,1) cy(:,:,2) cy(:,:,3) cy(:,:,4) cy(:,:,5) cy(:,:,6) cy(:,:,7) cy(:,:,8) cy(:,:,9) cy(:,:,10) cy(:,:,11) cy(:,:,12) cy(:,:,13) cy(:,:,14) cy(:,:,15) cy(:,:,16) cy(:,:,17) cy(:,:,18) cy(:,:,19) cy(:,:,20) cy(:,:,21) cy(:,:,22) cy(:,:,23) cy(:,:,24) cy(:,:,25) cy(:,:,26) cy(:,:,27) ... cy(:,:,3000];

 Réponse acceptée

Hayden Raabe-Garmon
Hayden Raabe-Garmon le 18 Juil 2022
Modifié(e) : Hayden Raabe-Garmon le 18 Juil 2022

0 votes

cy(:,:,1)=1
cy(:,:,2)=2
cy(:,:,3)=3
CY=squeeze(cy)'
CY =
1 2 3

3 commentaires

Hayden Raabe-Garmon
Hayden Raabe-Garmon le 18 Juil 2022
This would not be a Cell Array, this is a vector. A Cell/Cell Array is an entirely different class of variables
Mingde
Mingde le 18 Juil 2022
Thank you
Mingde
Mingde le 18 Juil 2022
Thank you. it is working.

Connectez-vous pour commenter.

Plus de réponses (1)

Image Analyst
Image Analyst le 18 Juil 2022

0 votes

Trust me, you don't want a cell array. I highly doubt it. It uses way more memory and is inefficient. You want code like @Hayden Raabe-Garmon gave you
CY=squeeze(cy)'
If you think you want a cell array, give justification (so I can talk you out of it).

3 commentaires

Mingde
Mingde le 18 Juil 2022
Thank you. it is working.
Mingde
Mingde le 19 Juil 2022
Modifié(e) : Mingde le 19 Juil 2022
cy(:,:,1)=1
cy(:,:,2)=2
cy(:,:,3)=3
cy(:,:,4)=4
cy(:,:,5)=5
cy(:,:,6)=6
cy(:,:,7)=7
cy(:,:,8)=8
cy(:,:,9)=9
...
cy(:,:,100)=100
How Can I use loop for mean each 3 cell array?
For example
mean(A)
cy(:,:,1)=1
cy(:,:,2)=2
cy(:,:,3)=3
mean(B)
cy(:,:,4)=4
cy(:,:,5)=5
cy(:,:,6)=6
...
mean(Z)
cy(:,:,98)=98
cy(:,:,99)=99
cy(:,:,100)=100
Image Analyst
Image Analyst le 19 Juil 2022
Again, we're not using cell arrays. And I don't know what range A, B, etc. cover. Do you just want the average of every group of 3 planes/slices? Like
A = cy(:, :, 1:3);
theMean = mean(A, 'all');

Connectez-vous pour commenter.

Catégories

En savoir plus sur Operators and Elementary Operations dans Centre d'aide et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by