getting the index after comparing two logicals

I compared two logicals and their results are as follows: a = [1 0 0 0 1] and b = [0 0 0 0 1]

1. I wanted to compare these logicals, identifying the corresponding columns where both 1's appear.
2. Identify which column that is: in this case, column 5.

Thanks

Answer 1

[DGM]

Something like this:

a = [1 0 0 0 1];
b = [0 0 0 0 1];

idx = find(a & b)

idx = 5

Though depending on your needs, the usage of find() may be an unnecessary complication, as the intersection of the two vectors can likely be used for logical indexing just the same.

Answer 2

[Mathieu NOE]

hello

see code below :

a = logical([1 0 0 0 1]) 
b = logical([0 0 0 0 1])
c = a & b
col_c_is_one = find(c)

gives the following results :

a = 1×5 logical array : 1 0 0 0 1

b = 1×5 logical array : 0 0 0 0 1

c = 1×5 logical array : 0 0 0 0 1

col_c_is_one = 5