How to delete an repeated values in matrix?

I have matrix like this, so how to delete repeated values in this case?

 [a b]=[197.9040   11.6502     41.6502   41.3856    41.3856     0      197.9040
         12.2180   51.2008     61.2008  104.3122   104.3122     0       12.2180];

[Jan]

Please post the wanted result also. Should the columns be unique? Or should all columns vanish, which appear more than once? Or do you mean the single elements?

[Matlab111]

wanted result:

 p=[11.6502 41.6502
    51.2008 61.2008];

Answer 1

[Stephen23]

A = [197.9040, 11.6502, 41.6502, 41.3856, 41.3856, 0, 197.9040, 12.2180, 51.2008, 61.2008, 104.3122, 104.3122, 0, 12.2180];
>> A(sum(bsxfun(@(a,b)abs(a-b)<1e-6,A,A(:)))<2)
ans =   
   11.6502   41.6502   51.2008   61.2008

Because your values are floating point it is best to avoid using eq, unique and the like, which only work for exactly identical values . Instead I used a tolerance of 1e-6, and values closer than this tolerance are assumed to be the same. You can change the tolerance to suit your values.

[Matlab111]

Stephen Cobeldick- i'm getting an error like this "Error using bsxfun

Non-singleton dimensions of the two input arrays must match each other."

[Stephen23]

I suspect that your array A is not a vector. I have slightly altered my code to work regardless of the shape of the input array A:

>> A = [197.9040, 11.6502, 41.6502, 41.3856, 41.3856, 0, 197.9040; 12.2180, 51.2008, 61.2008, 104.3122, 104.3122, 0, 12.2180];
>> A(sum(bsxfun(@(a,b)abs(a-b)<1e-6,A(:).',A(:)))<2)
ans = 
   11.6502   51.2008   41.6502   61.2008

Also I repeat the advice that I gave earlier: do not test for equality == or use unique to solve this problem.

[Matlab111]

Stephen Cobeldick- ya i'm not getting sir, try this one

question:

 c=[0.7893    0.8337    0.1479         0         0     0.1479       0.9993];

1.now i should delete the repeated values in that 'c'.

2.i should delete the values that is displayed before the zeros.

3.And finally i should delete zeros also.

Expected output:

 d=[0.9993];

[Stephen23]

You original question, which my code above solves exactly, does not mention anything about removing values before any zeros. You are changing the requirements, which makes it difficult for us to help you.

It is considered polite to Accept answers that solve your original question. I have answered your other question, about removing leading values, here:

http://www.mathworks.com/matlabcentral/answers/176676-how-to-delete-particular-values-in-this-matrix

Answer 2

[Roger Stafford]

If x is your array with repetitions

   [~,ia] = unique(x,'first','legacy');
   x = x(sort(ia));

Answer 3

[Andrei Bobrov]

x = [197.9040   11.6502     41.6502   41.3856    41.3856     0      197.9040
         12.2180   51.2008     61.2008  104.3122   104.3122     0       12.2180];

x = x(:);
[xx,~,c] = unique(x);
b = histc(c,1:max(c));
out = xx(b==1);