How do i delete the spaces that are in the middle of a string array?

str=' 123 456 ';

strtrim(str)

strfind('123 456',' ')

so far i know that using strtrim will remove the leading and trailing blanks in the string vector but how do i remove the space that is between 123 and 456? i can use strfind to help me know which element of the string vector is a blank space but how would i be able to delete the elements themselves?

Answer 1

[the cyclist]

Here is one way:

str='   123   456   ';
str(str==' ') = []

str = '123456'

This method relies on the fact that the white space is a space character (and not some of the other whitespace characters).

Answer 2

[Voss]

To delete elements from an array, set them to [] (or '').

% to removes spaces (' '):
str='   123   456   ';
str(str == ' ') = []

str = '123456'

% this also works:
str='   123   456   ';
str(str == ' ') = ''

str = '123456'

% to remove any whitespace:
str='   123   456   ';
str(isstrprop(str,'wspace')) = []

str = '123456'

Reference: https://www.mathworks.com/help/matlab/ref/isstrprop.html

Answer 3

[Paul]

replace seems to do the trick

Single char:

str='   123   456   ';
replace(str,whitespacePattern,'')

ans = '123456'

Cell array of chars

replace({str;str},whitespacePattern,'')

ans = 2×1 cell array
    {'123456'}
    {'123456'}

String array

str1 = string(str)

str1 = "   123   456   "

replace([str1;str1],whitespacePattern,'')

ans = 2×1 string array
    "123456"
    "123456"

Answer 4

[Githin George]

Hi Sameer,

My understanding is that you would like to remove any and all multiple spaces from your string to single space and trim the start and end. You could to use the following code to get it done.

mystr = ' Some      string       one   ';
% \s+ means multiple spaces
mystr = regexprep(mystr,'\s+',' ');
strtrim(mystr)

ans = 'Some string one'

I hope it helps!