How to hold different constellations using scatterhistogram?
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Dear all,
I hope the title is explicit enough, does anyone have an idea?
Thanks in advance.
Best regards,
louis
Example of code:
% signal vector
X = rand(1,1e3)+1i*rand(1,1e3);
% power in signal
PX= mean(abs(X).^2);
% noise of variance power in signal/10
B = PX/10*(randn(1,1e3)+1i*randn(1,1e3));
% signal + noise
Y = X+B;
% plot
hold all
scatterhistogram(real(X),imag(X))
scatterhistogram(real(Y),imag(Y))
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Réponse acceptée
Adam Danz
le 29 Juil 2022
Modifié(e) : Adam Danz
le 29 Juil 2022
scatterhistogram produces a ScatterHistogramChart object within a figure. When you call hold on, an axes is created if it doesn't already exist, and the axes is prepared to accept new objects. scatterhistogram tells you that you cannot assign the ScatterHistogramChart object to the axes.
Remove hold on so scatterhistogram can create the plot in a figure. Scatterhistogram() is not set up to combine two ScatterHistogramChart objects within the same set of axes.
3 commentaires
Adam Danz
le 1 Août 2022
Modifié(e) : Adam Danz
le 1 Août 2022
@Louis Tomczyk, you can, however, group your data together in a table and use a grouping variable to plot multiple sets of data into the same scatterhistogram chart. There are some examples in the documentation: scatterhistogram.
load patients
tbl = table(LastName,Diastolic,Systolic,Smoker)
s = scatterhistogram(tbl,'Diastolic','Systolic','GroupVariable','Smoker');
Adam Danz
le 2 Avr 2025
Alternatively, you can append the existing data using set(__). Here's a demo.
x = randn(1,50)*2+9;
y = randn(1,50)+5;
s = scatterhistogram(x,y);
Append s with additional data and create a grouping variable g to identify which group each datapoint belongs to. I created a new figure here for demonstration purposes.
figure
s = scatterhistogram(x,y);
x2 = rand(1,40)+6;
y2 = rand(1,40)*2+4;
g = [ones(numel(x),1); ones(numel(x2),1)+1];
set(s, 'XData', [x,x2], 'YData', [y,y2], 'GroupData', g);
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