Effacer les filtres
Effacer les filtres

there are two coupled differential equation, I try to solve that differential for the i = 1 to 5, but i think my for loop is incorrect.

2 vues (au cours des 30 derniers jours)
these are the differential equation I want to solve where the i = 1 to 5
I want to solve these differential equation but maybe the loop isn't correct or we can't apply loop here?
clc
ti = 0;
tf = 10E-6;
tspan = [ti tf];
a = 0.6;
n = 0.05;
tc = 10E-9;
r = 1.5;
F = 1;
k =1:1:5;
f = zeros(length(k),1) ;
for i = 1:length(k)
y(1) = A(i)
y(2) = O(i)
f = @(t,y) [
(-1/(2*tc)).*(1 - r/(1+ (A(i)^2)./F)).*A(i) + (n/(2*tc)).*((cos(O(i+1)- O(i))).*A(i+1) + (cos(O(i+1)- O(i))).*A(i-1)) ;
(a./(2*tc)).*(r/(1 + (A(i)^2)./F)) + (n/(2*tc)).*((A(i+1)./A(i)).*sin(O(i+1) - O(i)) - (A(i-1)./A(i)).*sin(O(i-1) - O(i)));
O(i+1) - O(i)
];
end
Unrecognized function or variable 'A'.
[time,Y] = ode45(f,tspan,[0;0;0]);
plot(time,Y(:,3))
  5 commentaires
SAHIL SAHOO
SAHIL SAHOO le 1 Août 2022
these are the equation that I want to solve by using ode45, where i = 1 to 5.
conditions A0 =0 and Ψ0 = 0 and whenever the i+1>=5 then (( i+1) - 5), means the A6 will be A1, A7 will be A2,
Ψ6 = Ψ1 and Ψ7 = Ψ2.
its like a circle i = 1 2 3 4 5 6 7
A1 A2 A3 A4 A5 A1A2....
Sam Chak
Sam Chak le 2 Août 2022
Won't this create an Ouroboros Loop that yields no solution?

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Réponses (1)

Walter Roberson
Walter Roberson le 31 Juil 2022
Note that because you use A(i+1) and O(i-1) you cannot produce plots for the first or last entries in A or O.
%number of data points
N = 5;
%put in your real A and O data here!!
A = randn(1,N);
O = rand(1,N) * 10;
%process data
ti = 0;
tf = 10E-6;
tspan = [ti tf];
a = 0.6;
n = 0.05;
tc = 10E-9;
r = 1.5;
F = 1;
k = 1:N;
f = zeros(N,1) ;
for i = 2:N-1
f = @(t,y) [
(-1/(2*tc)).*(1 - r/(1+ (A(i)^2)./F)).*A(i) + (n/(2*tc)).*((cos(O(i+1)- O(i))).*A(i+1) + (cos(O(i+1)- O(i))).*A(i-1)) ;
(a./(2*tc)).*(r/(1 + (A(i)^2)./F)) + (n/(2*tc)).*((A(i+1)./A(i)).*sin(O(i+1) - O(i)) - (A(i-1)./A(i)).*sin(O(i-1) - O(i)));
O(i+1) - O(i)
];
[time,Y] = ode45(f,tspan,[0;0;0]);
plot(time, Y(:,3), 'DisplayName', "i = " + i);
hold on
end
legend show
  5 commentaires
Torsten
Torsten le 31 Juil 2022
Usually, there are special "boundary" ODEs for the cases i=1 and i=N that differ from the ODEs for 1<i<N.
Walter Roberson
Walter Roberson le 31 Juil 2022
Note that once you have the definitions for the boundary ode, my recommendation would be to use the symbolic toolbox to set up the entire system of 15 coupled equations at the same time. Then follow the first example in the document for odeFunction() to convert to something that can be used with ode45

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