loop a matrix through disorder columns indices

I have a matrix A which has 100 rows and 5 columns, I would like to iterate the matrix with disorder indices of columns and save them in each iteration, column indices [2;5;3;4;1]. 1st iteration: get all the rows of A with column 2 then do some processes. 2nd iteration : get all the rows of A with columns 2 and 5. ..... last iteration: get all the rows and columns of A. Anyone helps me to implement it on Matlab environment please.

Answer 1

[Abderrahim. B]

Hi!

What about this below!

% Dummy A
A = randi(4, 100, 5 )  ;
% 
B = [] ;
for cIdx = [2 5 3 4 1]
    
 B = [B, A(:, cIdx )]
end

B = 100×1

3 3 3 4 1 4 1 2 1 4

B = 100×2

3 2 3 3 3 3 4 4 1 1 4 3 1 4 2 1 1 3 4 3

B = 100×3

3 2 2 3 3 1 3 3 3 4 4 1 1 1 1 4 3 3 1 4 4 2 1 1 1 3 2 4 3 2

B = 100×4

3 2 2 1 3 3 1 2 3 3 3 4 4 4 1 2 1 1 1 2 4 3 3 2 1 4 4 2 2 1 1 2 1 3 2 2 4 3 2 3

B = 100×5

3 2 2 1 4 3 3 1 2 1 3 3 3 4 2 4 4 1 2 1 1 1 1 2 4 4 3 3 2 4 1 4 4 2 3 2 1 1 2 4 1 3 2 2 2 4 3 2 3 2