can I apply a for loop inside the function so that I can make my program short?
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ti = 0;
tf = 10E-6;
tspan = [ti tf];
a = 0.6;
n = 0.05;
tc = 10E-9;
r = 1.5;
F = 10;
f = @(t,y) [
(-1/(2*tc)).*(1 - r/(1+ (y(1)^2)./F)).*y(1) + (n/(2*tc)).*((cos(y(6))).*y(2)) ;
(-1/(2*tc)).*(1 - r/(1+ (y(2)^2)./F)).*y(2) + (n/(2*tc)).*((cos(y(7))).*y(3) + (cos(y(6))).*y(1));
(-1/(2*tc)).*(1 - r/(1+ (y(3)^2)./F)).*y(3) + (n/(2*tc)).*((cos(y(8))).*y(4) + (cos(y(7))).*y(2));
(-1/(2*tc)).*(1 - r/(1+ (y(4)^2)./F)).*y(4) + (n/(2*tc)).*((cos(y(10))).*y(5) + (cos(y(8))).*y(8));
(-1/(2*tc)).*(1 - r/(1+ (y(5)^2)./F)).*y(5) + (n/(2*tc)).*((cos(y(9))).*y(4));
(a./(2*tc)).*( r/(1 + (y(2)^2)./F) - r/(1 + (y(1)^2)./F) ) + (n/(2*tc)).*(((y(3)./y(2)).*sin(y(7))) - (y(2)./y(1) + y(1)./y(2) ).*sin(y(6)) );
(a./(2*tc)).*( r/(1 + (y(3)^2)./F) - r/(1 + (y(2)^2)./F) ) + (n/(2*tc)).*(((y(4)./y(3)).*sin(y(8))) - (y(3)./y(2) + y(2)./y(3) ).*sin(y(7)) + (y(1)./y(2)).*sin(y(6)));
(a./(2*tc)).*( r/(1 + (y(4)^2)./F) - r/(1 + (y(3)^2)./F) ) + (n/(2*tc)).*(((y(5)./y(4)).*sin(y(8))) - (y(4)./y(3) + y(3)./y(4) ).*sin(y(8)) + (y(2)./y(3)).*sin(y(6)));
(a./(2*tc)).*( r/(1 + (y(5)^2)./F) - r/(1 + (y(4)^2)./F) ) + (n/(2*tc)).*(((y(3)./y(4)).*sin(y(8))) - (y(5)./y(4) + y(4)./y(5) ).*sin(y(9)));
(a./(2*tc)).*( - r/(1 + (y(5)^2)./F) ) + (n/(2*tc)).*((y(4)./y(5)).*sin(y(9)));
];
can I apply here the "for loop" inside where the function define. so the program will get short.
I wrote 10 equation in this, what if I want 20 equation ? can I apply for loop in this or any method.
[time,Y] = ode45(f,tspan,[1;1;1;1;1;1;1;1;1;1].*10E-6);
plot(time,Y(:,6))
hold on
plot(time,Y(:,7))
plot(time,Y(:,8))
plot(time,Y(:,9))
hold off
4 commentaires
per isakson
le 3 Août 2022
Now I think I understand your question.
Are there typos in your anonymous function? This looks suspect.
e.g. "y(8)" in three rows.
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/1087035/image.png)
Does your anonymous function agree with the equations in your comment?
Réponse acceptée
Torsten
le 3 Août 2022
Modifié(e) : Torsten
le 3 Août 2022
N = 5;
ti = 0;
tf = 10E-6;
tspan = [ti tf];
[time,Y] = ode45(@(t,y)f(t,y,N),tspan,[1;1;1;1;1;1;1;1;1;1].*10E-6);
function dy = f(t,y,N)
a = 0.6;
n = 0.05;
tc = 10E-9;
r = 1.5;
F = 10;
A = y(1:N);
phi = y(N+1:2*N);
dA = zeros(N,1);
dphi = zeros(N,1);
dA(1) = ...;
dphi(1) = ...;
for i = 2:N-1
dA(i) = ...;
dphi(i) = ...;
end
dA(N) = ...;
dphi(N) = ...;
dy = [dA;dphi];
end
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