I'm studying for an exam and I am stuck on this problem this is what I have so far...

1 vue (au cours des 30 derniers jours)
  • All of the elements in the first row are the column number +2 and all of the elements in the first column are the row number + 3.
  • All other elements in the matrix are the sum of the value above it and the value to the left of it
row = input('Enter value');
col = input('Enter value');
Mat=zeros(row,col)
for i=1:length(row)
for j = 1:length(col)
if i==1;
Mat(i,col(i)+2)
Mat(j,row(i)+3)
  1 commentaire
Torsten
Torsten le 4 Août 2022
All of the elements in the first row are the column number +2 and all of the elements in the first column are the row number + 3.
All of the elements in the first row are the column number +2
Thus Mat(1,1) = 3
all of the elements in the first column are the row number + 3
Thus Mat(1,1) = 4
Contradiction !

Connectez-vous pour commenter.

Réponses (1)

Image Analyst
Image Analyst le 7 Août 2022
The first index in a matrix if row and the second is column. In your loops j is the column. So you cannot have the first index be j.
Mat(j,row(i)+3) % NO!!!
"other elements in the matrix are the sum of the value above it and the value to the left of it"
so after you've set up the first row and column, start the loops at 2 and reference the matrix values above and to the left of it
% Add (above current element) + (left of current element) respectively
Mat(i, j) = Mat(i - 1, j) + Mat(i, j-1);

Catégories

En savoir plus sur Logical dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by