Vectorize an anonymous function

8 vues (au cours des 30 derniers jours)
AES
AES le 11 Août 2022
Commenté : Matt J le 11 Août 2022
I was wondering whether someone would be able to help/point me in the right direction for vectorizing a anonymous function?
I am trying to fit a multivariate gaussian distribution to data. Here is my code:
for n = 1:length(uniqPosOne)
gaussElpt = @(param) (param(1) + param(2).*(exp(-1/2 .* (uniqPosOne(n, :) - [param(3), param(4)]) * ...
([param(5), param(6); param(6), param(7)]).^(-1) * (uniqPosOne(n, :) - [param(3), param(4)]).')));
a = gaussElpt(startPoint);
tempList(n) = a;
end
I am trying to optimize the parameters that allow for me to fit my data (not shown), I use lsqnonlin.
uniqPosOne is a n x 2 array, params(1) and (2) are offset/gain, params(3) and (4) are vector means, and params(5), (6), (7) are part of covaraince matrix. The params are the parameters used by lsqnonlin to find the parameters with the lowest error.
I want to be able to have a nx2 array (uniqPosOne) and have the function evaluate each pair separately in a vectorized manner, currently I have been unable to do so as attempting vectorization results in a nxn, while I want a nx1.
The main reason is due to time to compute is rather long for a small subset of data. Any help is appreciated.
  3 commentaires
AES
AES le 11 Août 2022
Thank you!
Walter Roberson
Walter Roberson le 11 Août 2022
Or, better yet,
[param(5), param(6); param(6), param(7)] \ (uniqPosOne(n, :) - [param(3), param(4)]).'

Connectez-vous pour commenter.

Réponse acceptée

Matt J
Matt J le 11 Août 2022
Just replace all the uniqPosOne(n,:) with uniqPosOne:
gaussElpt = @(param) (param(1) + param(2).*(exp(-1/2 .* (uniqPosOne - [param(3), param(4)]) * ...
([param(5), param(6); param(6), param(7)]).^(-1) * (uniqPosOne - [param(3), param(4)]).')));
  5 commentaires
AES
AES le 11 Août 2022
Thank you, this is what I was looking to do. If you have time could you breifly explain, or point me towards some resources that may explain, this operation: sum((Sigma\dev).*dev)?
Matt J
Matt J le 11 Août 2022
Sigma\dev is the more recommended way of doing inv(Sigma)*dev.
See also Walter's comment above.

Connectez-vous pour commenter.

Plus de réponses (1)

Matt J
Matt J le 11 Août 2022
Modifié(e) : Matt J le 11 Août 2022
This FEX submission already appears to do what you want,

Catégories

En savoir plus sur Least Squares dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by