Match two variables list

Is there a way to transalte across these variable lists

c = ["80ms,110ms", "110ms,140ms", "140ms,195ms", "195ms,250ms", "250ms,400ms", "400ms,550ms", "550ms,725ms", "725ms,900ms"]
Times = {[0.08, 0.11], [0.11, 0.14], [0.14, 0.195], [0.195, 0.25], [0.25, 0.4], [0.4, 0.55], [0.55, 0.725], [0.725, 0.9]}'

such that if I have str.Var1 = {'80ms,110ms'} I can convert it to Times(1) = [0.08, 0.11]?

I am using the first variable to inform what the input should be (second variable) in a statistics test. So whatever value str.Var1 matches in c I get the correspomding value in Times.

> str.Var1

ans =

1×1 cell array

{'80ms,110ms'}



>> Times(1)

ans =

  1×1 cell array

    {1×2 double}

Answer 1

[Voss]

c = ["80ms,110ms", "110ms,140ms", "140ms,195ms", "195ms,250ms", "250ms,400ms", "400ms,550ms", "550ms,725ms", "725ms,900ms"]

c = 1×8 string array
    "80ms,110ms"    "110ms,140ms"    "140ms,195ms"    "195ms,250ms"    "250ms,400ms"    "400ms,550ms"    "550ms,725ms"    "725ms,900ms"

c_temp = c + ",";
Times = num2cell(reshape(sscanf([c_temp{:}],'%fms,')/1000,2,[]).',2)

Times = 8×1 cell array
    {[0.0800 0.1100]}
    {[0.1100 0.1400]}
    {[0.1400 0.1950]}
    {[0.1950 0.2500]}
    {[0.2500 0.4000]}
    {[0.4000 0.5500]}
    {[0.5500 0.7250]}
    {[0.7250 0.9000]}

Answer 2

[Les Beckham]

Perhaps what you want is this:

c = ["80ms,110ms", "110ms,140ms", "140ms,195ms", "195ms,250ms", "250ms,400ms", "400ms,550ms", "550ms,725ms", "725ms,900ms"];
Times = {[0.08, 0.11], [0.11, 0.14], [0.14, 0.195], [0.195, 0.25], [0.25, 0.4], [0.4, 0.55], [0.55, 0.725], [0.725, 0.9]}';
str.Var1 = {'80ms,110ms'};
cellresult = Times(strcmp(str.Var1, c));
result = cellresult{1} % extract the double vector from the cell

result = 1×2

0.0800 0.1100