Vector as ItemsData property in List Box

11 views (last 30 days)
Hi all,
im coding a fairly easy app with app designer and im struggling with the input/output for List Box property "ItemsData".
What i want to do is to show the user 2 options ("Items") in a list-box. These options then lead to vectors of 2 numbers ("ItemsData"). Lets say:
With ItemsData(Option 1) = [2950 3350] and ItemsData(Option 2) = [3600 4500]
Now i want to use these 2 integers in my main function and i cant figure out how to do the indexing right. I tried using a cell array as ItemsData with combined indexing:
A = B{1,1}(1,1)
which leeds to an error because of the curly brackets.
If it is any easier with a Switch or DropDown its fine too! There are just 2 options.
Thanks for any help on this!

Accepted Answer

Oskar Kilgus
Oskar Kilgus on 21 Aug 2022
I found a way to do it (If anyone is having trouble with this issue in the future)
1) List-Box ItemsData as 1x2 numeric vector:
[1 2]
2) value-changed function callback:
% Value changed function: choosefromListBox
function choosefromListBoxValueChanged(app, event)
app.whatever = str2num(app.choosefromListBox.Value)
end
3) reference in other function:
app.whatever(1,1) %returns 1
______________________________
Thanks @Simon Chan for your effort!

More Answers (1)

Simon Chan
Simon Chan on 21 Aug 2022
Suppose the listbox is defined as follows and ItemsData are given in your example.
app.ListBox = uilistbox(app.UIFigure);
You may get the data directly via the following:
A = app.ListBox.Value
  8 Comments
Oskar Kilgus
Oskar Kilgus on 21 Aug 2022
Edited: Oskar Kilgus on 21 Aug 2022
I tried exactly that (see the code i supplied) and it resulted in the error
"'Value' must be a double scalar within the range of 'Limits'."
The interesting value at the end of the function is m(o,:) = mean(p). I tried it again and now i end up with m=[0; NaN]. For the next iteration i still end up with the error message above!

Sign in to comment.

Categories

Find more on Migrate GUIDE Apps in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by