Effacer les filtres
Effacer les filtres

did I plot the "r" factor correctly in it?

1 vue (au cours des 30 derniers jours)
SAHIL SAHOO
SAHIL SAHOO le 27 Août 2022
Réponse apportée : Karim le 29 Août 2022
ti = 0;
tf = 1E-4;
tspan=[ti tf];
y0=[1; 1; 1; 1; 1; 1; 1; 1; 1; 1; 0; 0; 0; 0; 0];
N = 5;
tp = 5.4E-9;
[T,Y]= ode45(@(t,y) rate_eq(t,y,N),tspan,y0);
% did this r part is correct?
r = (exp((0+1i).*Y(:,11)) + exp((0+1i).*Y(:,12)) + exp((0+1i).*Y(:,13)) + exp((0+1i).*Y(:,14)) + exp((0+1i).*Y(:,15)))./5 ;
plot(T./tp,r);
xlabel('time')
ylabel('order parameter')
function dy = rate_eq(t,y,N)
dy = zeros(3*N,1);
P = 16.7;
a = 0.1;
tc = 230E-6;
tp = 5.4E-9;
o1 = 5308;
o2 = 4008;
o3 = 7009;
o4 = 6008;
o5 = 7080;
k1 = 1E-3;
k2 = 1E-3;
k3 = 1E-3;
k4 = 1E-3;
k5 = 1E-3;
dy(1) = (P - y(1).*((abs(y(6)))^2 +1))./tc;
dy(2) = (P - y(2).*((abs(y(7)))^2 +1))./tc;
dy(3) = (P - y(3).*((abs(y(8)))^2 +1))./tc;
dy(4) = (P - y(4).*((abs(y(9)))^2 +1))./tc;
dy(5) = (P - y(5).*((abs(y(10)))^2 +1))./tc;
dy(6)= (y(1)-a).*((y(6))./tp) + (k1./tp).*(y(7)).*cos(y(11)) + (k5./tp).*(y(10))*cos(y(15));
dy(7)= (y(2)-a).*((y(7))./tp) + (k2./tp).*(y(8)).*cos(y(12)) + (k1./tp).*(y(6))*cos(y(11));
dy(8)= (y(3)-a).*((y(8))./tp) + (k3./tp).*(y(9)).*cos(y(13)) + (k2./tp).*(y(7))*cos(y(12));
dy(9)= (y(4)-a).*((y(9))./tp) + (k4./tp).*(y(10)).*cos(y(14)) + (k3./tp).*(y(8))*cos(y(13));
dy(10)= (y(5)-a).*((y(10))./tp) + (k5./tp).*(y(9)).*cos(y(14)) +(k4./tp).* (y(6))*cos(y(15));
dy(11) = o1 - (k1./tp).*(y(6)/y(7)).*(sin(y(11))) - (k1./tp).*(y(10)/y(6)).*(sin(y(11))) + (k2./tp).*(y(8)./y(7))*sin(y(12)) + (k5./tp).*(y(10)/y(6)).*sin(y(15));
dy(12) = o2 - (k2./tp).*(y(7)/y(8)).*(sin(y(12))) - (k2./tp).*(y(8)/y(7)).*(sin(y(12))) + (k3./tp).*(y(9)./y(8))*sin(y(13)) + (k1./tp).*(y(6)/y(7)).*sin(y(11));
dy(13) = o3 - (k3./tp).*(y(8)/y(9)).*(sin(y(13))) - (k3./tp).*(y(9)/y(8)).*(sin(y(13))) + (k4./tp).*(y(10)./y(9))*sin(y(14)) + (k2./tp).*(y(7)/y(8)).*sin(y(12));
dy(14) = o4 - (k4./tp).*(y(9)/y(10)).*(sin(y(14))) - (k4./tp).*(y(10)/y(9)).*(sin(y(14))) + (k5./tp).*(y(6)./y(10))*sin(y(15)) + (k3./tp).*(y(8)/y(9)).*sin(y(13));
dy(15) = o5 - (k5./tp).*(y(10)/y(6)).*(sin(y(15))) - (k5./tp).*(y(6)/y(10)).*(sin(y(15))) + (k1./tp).*(y(7)./y(6))*sin(y(11)) + (k4./tp).*(y(9)/y(10)).*sin(y(14));
end
============================
= r, this is the equation of r here and i want to calculate the r value, and the ϕ1=Y(:,11),ϕ2 = Y(:,12),ϕ3 = Y(:,13), ϕ4 = Y(:,14), ϕ5 = Y(:,15) and N =5
please tell me did I plot r correctly or not?

Réponse acceptée

Karim
Karim le 29 Août 2022
at first glance you still need to take the absolute value, see below
ti = 0;
tf = 1E-4;
tspan=[ti tf];
y0=[1; 1; 1; 1; 1; 1; 1; 1; 1; 1; 0; 0; 0; 0; 0];
N = 5;
tp = 5.4E-9;
[T,Y]= ode45(@(t,y) rate_eq(t,y,N),tspan,y0);
% evaluate r
r = ( exp(1i*Y(:,11)) + exp(1i*Y(:,12)) + exp(1i*Y(:,13)) + exp(1i*Y(:,14)) + exp(1i*Y(:,15)) ) / N;
r = abs( r );
plot(T./tp,r);
xlabel('time')
ylabel('order parameter')
function dy = rate_eq(t,y,N)
dy = zeros(3*N,1);
P = 16.7;
a = 0.1;
tc = 230E-6;
tp = 5.4E-9;
o1 = 5308;
o2 = 4008;
o3 = 7009;
o4 = 6008;
o5 = 7080;
k1 = 1E-3;
k2 = 1E-3;
k3 = 1E-3;
k4 = 1E-3;
k5 = 1E-3;
dy(1) = (P - y(1).*((abs(y(6)))^2 +1))./tc;
dy(2) = (P - y(2).*((abs(y(7)))^2 +1))./tc;
dy(3) = (P - y(3).*((abs(y(8)))^2 +1))./tc;
dy(4) = (P - y(4).*((abs(y(9)))^2 +1))./tc;
dy(5) = (P - y(5).*((abs(y(10)))^2 +1))./tc;
dy(6)= (y(1)-a).*((y(6))./tp) + (k1./tp).*(y(7)).*cos(y(11)) + (k5./tp).*(y(10))*cos(y(15));
dy(7)= (y(2)-a).*((y(7))./tp) + (k2./tp).*(y(8)).*cos(y(12)) + (k1./tp).*(y(6))*cos(y(11));
dy(8)= (y(3)-a).*((y(8))./tp) + (k3./tp).*(y(9)).*cos(y(13)) + (k2./tp).*(y(7))*cos(y(12));
dy(9)= (y(4)-a).*((y(9))./tp) + (k4./tp).*(y(10)).*cos(y(14)) + (k3./tp).*(y(8))*cos(y(13));
dy(10)= (y(5)-a).*((y(10))./tp) + (k5./tp).*(y(9)).*cos(y(14)) +(k4./tp).* (y(6))*cos(y(15));
dy(11) = o1 - (k1./tp).*(y(6)/y(7)).*(sin(y(11))) - (k1./tp).*(y(10)/y(6)).*(sin(y(11))) + (k2./tp).*(y(8)./y(7))*sin(y(12)) + (k5./tp).*(y(10)/y(6)).*sin(y(15));
dy(12) = o2 - (k2./tp).*(y(7)/y(8)).*(sin(y(12))) - (k2./tp).*(y(8)/y(7)).*(sin(y(12))) + (k3./tp).*(y(9)./y(8))*sin(y(13)) + (k1./tp).*(y(6)/y(7)).*sin(y(11));
dy(13) = o3 - (k3./tp).*(y(8)/y(9)).*(sin(y(13))) - (k3./tp).*(y(9)/y(8)).*(sin(y(13))) + (k4./tp).*(y(10)./y(9))*sin(y(14)) + (k2./tp).*(y(7)/y(8)).*sin(y(12));
dy(14) = o4 - (k4./tp).*(y(9)/y(10)).*(sin(y(14))) - (k4./tp).*(y(10)/y(9)).*(sin(y(14))) + (k5./tp).*(y(6)./y(10))*sin(y(15)) + (k3./tp).*(y(8)/y(9)).*sin(y(13));
dy(15) = o5 - (k5./tp).*(y(10)/y(6)).*(sin(y(15))) - (k5./tp).*(y(6)/y(10)).*(sin(y(15))) + (k1./tp).*(y(7)./y(6))*sin(y(11)) + (k4./tp).*(y(9)/y(10)).*sin(y(14));
end

Plus de réponses (0)

Catégories

En savoir plus sur Historical Contests dans Help Center et File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by