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Heatmap plot temperature vs time

16 vues (au cours des 30 derniers jours)
Laura Guarino
Laura Guarino le 28 Août 2022
Commenté : Walter Roberson le 28 Août 2022
I need to create a heatmap showing the temperature trend as a function of time acquired from ten sensors equally spaced. I have tried to plot it starting from a two columns matrix where the first one is a vector relevant to time while the second one is the corresponding temperature. I have tried with the following code:
heatmap(tbl,'time','temperature','Colormap',redbluecmap);
However, it shows me this error message: The name 'time' is not an accessible property for an instance of class 'matlab.graphics.chart.HeatmapChart'.
How can I fix it?
I should obtain something similar to this:
  1 commentaire
Walter Roberson
Walter Roberson le 28 Août 2022
What shows up for
class(tbl)
tbl.Properties.VariableNames

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Réponse acceptée

Abderrahim. B
Abderrahim. B le 28 Août 2022
Hi!
I know what is the issue. You have a timetable not a table and the first column related to time is not considered as variable . Solution: Convert to table
Demo below:
clear
MeasurementTime = datetime({'2015-12-18 08:03:05';'2015-12-18 10:03:17';'2015-12-18 12:03:13'});
Temp = [37.3;39.1;42.3];
Pressure = [30.1;30.03;29.9];
WindSpeed = [13.4;6.5;7.3];
TT = timetable(MeasurementTime,Temp,Pressure,WindSpeed)
TT = 3×3 timetable
MeasurementTime Temp Pressure WindSpeed ____________________ ____ ________ _________ 18-Dec-2015 08:03:05 37.3 30.1 13.4 18-Dec-2015 10:03:17 39.1 30.03 6.5 18-Dec-2015 12:03:13 42.3 29.9 7.3
TT = timetable2table(TT) ;
heatmap(TT, "MeasurementTime", "Temp")
  3 commentaires
Abderrahim. B
Abderrahim. B le 28 Août 2022
You are right.I did not read carefully the question. Need to edit or remove this answer. Thanks Walter.
Walter Roberson
Walter Roberson le 28 Août 2022
The error they received would be consistent with the possibility that they had previously done
tbl = heatmap(...)
and are now trying to do
heatmap(tbl, ...)

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