Which solver can solve this equation for V. Result should be around 59. I tested the to halfs of the equation on python. Thank you for your directions in the first place.
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Karl
le 30 Août 2022
Réponse apportée : John D'Errico
le 30 Août 2022
(650.5-(500-V))/((150.5-V*0.5)/(V*0.8660254037844386)) = ((500-V)-((650.5/(((150.5-V*0.5)/(V*0.8660254037844386))+1.364))*1.364))/((((((((500*2-(500-V))/3.052050807569)*1.7320508075688773+(500-V))-(500-V))/((((((500*2-(500-V))/3.052050807569)*1.7320508075688773+(500-V))-(500-V))/(264.77-(650.5-(500-V))/(284.7/(264.77-(284.7/((150.5-V*0.5)/(V*0.8660254037844386)))))))+1.7320508075688773))*1.7320508075688773+(500-V))-((650.5/(((150.5-V*0.5)/(V*0.8660254037844386))+1.364))*1.364))/(268.18-(((((((500*2-(500-V))/3.052050807569)*1.7320508075688773+(500-V))-(500-V))/((((((500*2-(500-V))/3.052050807569)*1.7320508075688773+(500-V))-(500-V))/(264.77-(650.5-(500-V))/(284.7/(264.77-(284.7/((150.5-V*0.5)/(V*0.8660254037844386)))))))+1.7320508075688773))*1.7320508075688773+(500-V))-365.8)/(284.7/(268.18-((650.5-(500-V))/1.7320508075688773))))) monospaced
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Réponse acceptée
Torsten
le 30 Août 2022
Modifié(e) : Torsten
le 30 Août 2022
fun = @(V)((500-V)-((650.5/(((150.5-V*0.5)/(V*0.8660254037844386))+1.364))*1.364))/((((((((500*2-(500-V))/3.052050807569)*1.7320508075688773+(500-V))-(500-V))/((((((500*2-(500-V))/3.052050807569)*1.7320508075688773+(500-V))-(500-V))/(264.77-(650.5-(500-V))/(284.7/(264.77-(284.7/((150.5-V*0.5)/(V*0.8660254037844386)))))))+1.7320508075688773))*1.7320508075688773+(500-V))-((650.5/(((150.5-V*0.5)/(V*0.8660254037844386))+1.364))*1.364))/(268.18-(((((((500*2-(500-V))/3.052050807569)*1.7320508075688773+(500-V))-(500-V))/((((((500*2-(500-V))/3.052050807569)*1.7320508075688773+(500-V))-(500-V))/(264.77-(650.5-(500-V))/(284.7/(264.77-(284.7/((150.5-V*0.5)/(V*0.8660254037844386)))))))+1.7320508075688773))*1.7320508075688773+(500-V))-365.8)/(284.7/(268.18-((650.5-(500-V))/1.7320508075688773)))))-(650.5-(500-V))/((150.5-V*0.5)/(V*0.8660254037844386));
format long
V = fsolve(fun,50)
fun(V)
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Bruno Luong
le 30 Août 2022
Modifié(e) : Bruno Luong
le 30 Août 2022
I would use fzero for singlle variable function
fun = @(V)((500-V)-((650.5/(((150.5-V*0.5)/(V*0.8660254037844386))+1.364))*1.364))/((((((((500*2-(500-V))/3.052050807569)*1.7320508075688773+(500-V))-(500-V))/((((((500*2-(500-V))/3.052050807569)*1.7320508075688773+(500-V))-(500-V))/(264.77-(650.5-(500-V))/(284.7/(264.77-(284.7/((150.5-V*0.5)/(V*0.8660254037844386)))))))+1.7320508075688773))*1.7320508075688773+(500-V))-((650.5/(((150.5-V*0.5)/(V*0.8660254037844386))+1.364))*1.364))/(268.18-(((((((500*2-(500-V))/3.052050807569)*1.7320508075688773+(500-V))-(500-V))/((((((500*2-(500-V))/3.052050807569)*1.7320508075688773+(500-V))-(500-V))/(264.77-(650.5-(500-V))/(284.7/(264.77-(284.7/((150.5-V*0.5)/(V*0.8660254037844386)))))))+1.7320508075688773))*1.7320508075688773+(500-V))-365.8)/(284.7/(268.18-((650.5-(500-V))/1.7320508075688773)))))-(650.5-(500-V))/((150.5-V*0.5)/(V*0.8660254037844386));
format long
V = fzero(fun,50)
fun(V)
Plus de réponses (1)
John D'Errico
le 30 Août 2022
So the second time you asked this question, you provided values for the other variables. I'll first put it in symbolic form so we can see what you have.
syms V
F_V = -(650.5-(500-V))/((150.5-V*0.5)/(V*0.8660254037844386)) + ((500-V)-((650.5/(((150.5-V*0.5)/(V*0.8660254037844386))+1.364))*1.364))/((((((((500*2-(500-V))/3.052050807569)*1.7320508075688773+(500-V))-(500-V))/((((((500*2-(500-V))/3.052050807569)*1.7320508075688773+(500-V))-(500-V))/(264.77-(650.5-(500-V))/(284.7/(264.77-(284.7/((150.5-V*0.5)/(V*0.8660254037844386)))))))+1.7320508075688773))*1.7320508075688773+(500-V))-((650.5/(((150.5-V*0.5)/(V*0.8660254037844386))+1.364))*1.364))/(268.18-(((((((500*2-(500-V))/3.052050807569)*1.7320508075688773+(500-V))-(500-V))/((((((500*2-(500-V))/3.052050807569)*1.7320508075688773+(500-V))-(500-V))/(264.77-(650.5-(500-V))/(284.7/(264.77-(284.7/((150.5-V*0.5)/(V*0.8660254037844386)))))))+1.7320508075688773))*1.7320508075688773+(500-V))-365.8)/(284.7/(268.18-((650.5-(500-V))/1.7320508075688773)))))
Note that I put both onto the same side of the equation, so I can plot it, as a function of V.
fplot(F_V,[0,100])
There does appear to be a solution for this relation. As I said in my response the FIRST time you asked the question, there will be NO analytical solution. Don't even bother to look.
Just use fzero.
F_v = @(V) -(650.5-(500-V))/((150.5-V*0.5)/(V*0.8660254037844386)) + ((500-V)-((650.5/(((150.5-V*0.5)/(V*0.8660254037844386))+1.364))*1.364))/((((((((500*2-(500-V))/3.052050807569)*1.7320508075688773+(500-V))-(500-V))/((((((500*2-(500-V))/3.052050807569)*1.7320508075688773+(500-V))-(500-V))/(264.77-(650.5-(500-V))/(284.7/(264.77-(284.7/((150.5-V*0.5)/(V*0.8660254037844386)))))))+1.7320508075688773))*1.7320508075688773+(500-V))-((650.5/(((150.5-V*0.5)/(V*0.8660254037844386))+1.364))*1.364))/(268.18-(((((((500*2-(500-V))/3.052050807569)*1.7320508075688773+(500-V))-(500-V))/((((((500*2-(500-V))/3.052050807569)*1.7320508075688773+(500-V))-(500-V))/(264.77-(650.5-(500-V))/(284.7/(264.77-(284.7/((150.5-V*0.5)/(V*0.8660254037844386)))))))+1.7320508075688773))*1.7320508075688773+(500-V))-365.8)/(284.7/(268.18-((650.5-(500-V))/1.7320508075688773)))));
[Vsol,fval,exitflag] = fzero(F_v,[0,100])
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