How to print multiple Values using sprintf In matlab

30 vues (au cours des 30 derniers jours)
Stephen john
Stephen john le 31 Août 2022
Commenté : Stephen john le 31 Août 2022
Hello Everyone, I hope you are doing well.
I have the following dataset which consists of following values . I am trying to print the values using sprintf. But extra values are printing
The sprintf output should be like
'DS Levels: 2
DS Value: [333 343]
DS Length: [ 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 19 23]
Maximum Value of DS:343'
Minimum Value of DS:333'
but i am getting the ouput like the following
'DS Levels: 2
DS Value: [333 343 1]
DS Length: [2 3 4 ]
Maximum Value of DS:5
Minimum Value of DS:6
DS Levels: 7
DS Value: [8 9 10]
DS Length: [11 12 13 ]
Maximum Value of DS:14
Minimum Value of DS:15
DS Levels: 16
DS Value: [17 19 23]
DS Length: [343 333 '
z=1;
pred1 = sprintf('DS Levels: %d\n DS Value: [%d %d %d]\n DS Length: [%d %d %d ]\n Maximum Value of DS:%d\n Minimum Value of DS:%d\n ',CombineOutput(z).PRFStructure.Levels,unique(CombineOutput(z).PRFStructure.DSPRFValue),unique(CombineOutput(z).PRFStructure.DSlength),CombineOutput(z).PRFStructure.DSmaximum,CombineOutput(z).PRFStructure.DSminimum);
pred1
%% Its print the values the like following
% % % % 'DS Levels: 2
% DS Value: [333 343 1]
% DS Length: [2 3 4 ]
% Maximum Value of DS:5
% Minimum Value of DS:6
% DS Levels: 7
% DS Value: [8 9 10]
% DS Length: [11 12 13 ]
% Maximum Value of DS:14
% Minimum Value of DS:15
% DS Levels: 16
% DS Value: [17 19 23]
% DS Length: [343 333 '

Réponse acceptée

Stephen23
Stephen23 le 31 Août 2022
Modifié(e) : Stephen23 le 31 Août 2022
Rather than hard-coding a fixed number of values to print, I recommend writing more robust code using STRING &JOIN or COMPOSE or SPRINTF to first create text of any number of values, then provide those to SPRINTF. For example:
S = load('matlab.mat');
T = S.CombineOutput.PRFStructure
T = 1×5 table
DSPRFValue DSlength Levels DSmaximum DSminimum ___________ ___________ ______ _________ _________ 1×85 double 1×85 double 2 343 333
Z = sprintf('DS Levels: %d\nDS Value: [%s]\nDS Length: [%s]\nMaximum Value of DS:%d\nMinimum Value of DS:%d',...
T.Levels, join(string(T.DSPRFValue),' '), join(string(T.DSlength),' '), T.DSmaximum, T.DSminimum)
Z =
'DS Levels: 2 DS Value: [333 343 333 343 333 343 333 343 333 343 333 343 333 343 333 343 333 343 333 343 333 343 333 343 333 343 333 343 333 343 333 343 333 343 333 343 333 343 333 343 333 343 333 343 333 343 333 343 333 343 333 343 333 343 333 343 333 343 333 343 333 343 333 343 333 343 333 343 333 343 333 343 333 343 333 343 333 343 333 343 333 343 333 343 333] DS Length: [17 16 16 17 17 16 16 17 17 16 16 17 11 12 17 16 14 17 6 14 16 16 17 4 2 3 6 12 17 8 4 3 4 6 17 13 8 1 1 10 3 2 17 14 7 14 19 14 6 15 16 17 17 6 3 9 4 2 17 7 3 5 4 1 17 10 8 5 17 14 10 12 17 16 16 17 17 10 23 16 16 17 17 16 14] Maximum Value of DS:343 Minimum Value of DS:333'
If the text is ultimately going to be displayed in the command window or printed to a file, then skip SPRINTF and just go directly to FPRINTF:
fprintf('DS Levels: %d\nDS Value: [%d', T.Levels, T.DSPRFValue(1));
fprintf(' %d', T.DSPRFValue(2:end));
fprintf(']\nDS Length: [%d',T.DSlength(1));
fprintf(' %d', T.DSlength(2:end));
fprintf(']\nMaximum Value of DS:%d\nMinimum Value of DS:%d', T.DSmaximum, T.DSminimum)
That would probably be the most efficient approach.
  3 commentaires
Stephen23
Stephen23 le 31 Août 2022
Modifié(e) : Stephen23 le 31 Août 2022
"Can you please modified it"
You can use indexing to access cell array content:
S = load('newone.mat');
T = S.CombineOutput.PRFStructure
T = 1×4 table
StagLevels StagPRFValue StaggMinimumValue StaggMaximumValue __________ ____________ _________________ _________________ 9 {9×1 double} 2838 2784
% vvv very basic cell array indexing
join(string(T.StagPRFValue{1}),' ')
ans = "2784 2787 2789 2793 2801 2802 2823 2824 2838"
Stephen john
Stephen john le 31 Août 2022
@Stephen23 Thanks

Connectez-vous pour commenter.

Plus de réponses (1)

Karim
Karim le 31 Août 2022
Modifié(e) : Karim le 31 Août 2022
This is due to the amount %d you have used. Only use 2 of them for DS Value and 19 for DS Length
update added a 'print string' which updates the amount of %d's automatically based on the struct
load(websave('myFile', "https://nl.mathworks.com/matlabcentral/answers/uploaded_files/1112565/matlab.mat"))
z = 1;
% create the print string
PrintStr = join(["DS Levels: ",repmat("%d ",1,numel(CombineOutput(z).PRFStructure.Levels)),"\n"...
"DS Value: ", repmat("%d ",1,numel(unique(CombineOutput(z).PRFStructure.DSPRFValue))),"\n"...
"DS Length: ",repmat("%d ",1,numel(unique(CombineOutput(z).PRFStructure.DSlength))),"\n"...
"Maximum Value of DS: ",repmat("%d ",1,numel(CombineOutput(z).PRFStructure.DSmaximum)),"\n"...
"Minimum Value of DS: ",repmat("%d ",1,numel(CombineOutput(z).PRFStructure.DSminimum)),"\n"]);
% print the text
pred1 = sprintf(PrintStr,CombineOutput(z).PRFStructure.Levels,unique(CombineOutput(z).PRFStructure.DSPRFValue),unique(CombineOutput(z).PRFStructure.DSlength),CombineOutput(z).PRFStructure.DSmaximum,CombineOutput(z).PRFStructure.DSminimum);
pred1
pred1 =
"DS Levels: 2 DS Value: 333 343 DS Length: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 19 23 Maximum Value of DS: 343 Minimum Value of DS: 333 "
  2 commentaires
Stephen john
Stephen john le 31 Août 2022
@Karim But it need to be uniform sometime i get DS Levels: 3 sometimes its DS Levels: 4
and DSValue also change with Respect to Levels.
Karim
Karim le 31 Août 2022
I updated the answer so that the amount of %d's is determined automatically

Connectez-vous pour commenter.

Catégories

En savoir plus sur Data Type Conversion dans Help Center et File Exchange

Produits


Version

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by