Effacer les filtres
Effacer les filtres

What to change in code?

3 vues (au cours des 30 derniers jours)
Steve
Steve le 10 Oct 2011
Hello Experts,
Given the following code:
How to transform it to work with the full polynomial, not from a(1).
I really need someone to help me with this issue urgently.
Thanks in advance!
  3 commentaires
bym
bym le 10 Oct 2011
whats wrong with answers here? http://www.mathworks.com/matlabcentral/answers/17931-bairstow-method-to-find-polynomial-roots-matlab-code-problem
Steve
Steve le 10 Oct 2011
Hello proecsm,
Thanks for commenting, I am going to publish the problem and what I have done, so please be so kind and help me.

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Réponses (1)

Wayne King
Wayne King le 10 Oct 2011
Steve, I have the same question proecsm asks, what's wrong with the answer Walter and I gave you in your earlier post? If you want the roots of:
p(x) = 2*x^2+2*x+1
You can do that with
roots([2 2 1])
or using your function, simply divide through by 2 and don't include the leading 1.
[rts,it]=bairstow([1 1/2],2,1e-3);
As I read Walter's post that is exactly what he clearly explained to you. And I certainly tried to explain very much the same thing.
It seems to me that you're much better off learning to provide the correct input to the funtion you have instead of trying to modify it to accept the input you want to give it.
  1 commentaire
Walter Roberson
Walter Roberson le 10 Oct 2011
Yup, exactly.
if a(1) ~= 1; a = a ./ a(1); end
a = a(2:end);
The test for 1 is merely an optimization. You could just use
a = a(2:end) ./ a(1);

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