Community Profile # bym

### NCSU

Active since 2011

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linear system of equations
Your equations are not independent. The second is 2 times the first

environ 7 ans ago | 1

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Troubles with interaction problem
here is a partial answer, without using symbolic tool box...see my comment above and you should be able to adapt the code to wha...

plus de 7 ans ago | 0

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Why is my Simpson's 3/8 code not producing the correct values?
your first loop should start at 2, second at 3, third at 4. Set end points for all loops at n-1. Make sure n is divisible by 3 ...

plus de 7 ans ago | 1

how to create customized curve ( only know the shape )
maybe this or similar would help <http://www.mathworks.com/matlabcentral/fileexchange/7173-grabit>

environ 8 ans ago | 0

problem about ODE (Rayleigh-Plesset Equation) error in ode15s
check your call to ode15s [T,R] = ode15s('RP',[0 3e-8],[1e-6 70]); %your code what does the following give you? [T,...

environ 8 ans ago | 0

Problem in reading data from Excel sheet and copying it in 2d array
reverse i & j ? %copying data from the Numeric array to P for i = 1: 1:1110 for j = 1: 1 : 6...

environ 8 ans ago | 1

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Issue with lsqcurvefit and langmuir type equation
see comments in revised code below myfun = @(x,xdata) (x(1)*x(2).*xdata)./(1+x(2).*xdata); %added elementwise operators ./ ...

environ 8 ans ago | 0

how do i save looped output into 1 variable matrix
c=19; % D=[]; p = zeros(c,1); % preallocate for k=1:c; Z=[X(:,1),Y(:,1)]; p(k)=anova1(Z); %D=save(p) unecessary %X(...

environ 8 ans ago | 0

Plese help me. Matlab 'while' loop. A set of data is given..?
x =[ 8, 10, 12, 14, 16] find(x>=11,1) ans = 3 *edit*----------------------------- x = 8 10 ...

environ 8 ans ago | 0

Finding coefficients and constant for multivariable linear equation.
You don't have enough points. 4 points < 5 unknowns

environ 8 ans ago | 0

Vandermonde Matrix and an Error Vector
X = V\B

environ 8 ans ago | 0

gaussian histogram so that area is equal to one.
it does not make sense to me to have the number of bins equal to your length of data. The purpose of a histogram is to describe...

plus de 8 ans ago | 0

error message using polyfit (nonlinear regression)
I think it is obvious from the message; you don't have a enough data points to fit the polynomial uniquely. Like fitting a line ...

plus de 8 ans ago | 0

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Don't define wn as symbolic vo=input('vo='); xo=input('xo='); wn=input('wn='); syms t; %syms wn; comment this...

plus de 8 ans ago | 0

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Plot inside a "for" loop
Please see comments in code. I checked a couple of values and they agree with your excel table, but it is up to you to verify t...

plus de 8 ans ago | 0

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finding the breakeven point
Are you sure your equation is right? Anyway here is an example with a modified equation: f = @(c) log((c-1)./log(1+c)) ...

plus de 8 ans ago | 0

sum(w) and ones(1,size(w,2))*w' results totally different numbers
try ones(size(w))*w.'

plus de 8 ans ago | 0

Ttest problem with alpha
you do not need to pass 'Alpha' to the function, you are getting the error because you are trying to pass a string when it is ex...

plus de 8 ans ago | 0

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%{ were you thinking of multiple lines of comments? (curly braces,not tildes) }%

plus de 8 ans ago | 1

Curve fitting to get gamma curve parameter
If you have the statistics toolbox, you can use: gamfit()

plus de 8 ans ago | 0

to find area of parabola?
x=[7.8 8.25 8.55]; y=[0.96 0.99 0.94]; p=polyfit(x,y,2); %f=polyval(x,p); x & p should be reversed ...

plus de 8 ans ago | 0

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Plot empties after using datetick
clc;clear; close all startDate = datenum('01-01-2009'); endDate = datenum('12-31-2009'); xData = linspace(startDa...

plus de 8 ans ago | 1

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How to plot in 4_D?
look at the documentation for slice by typing in the command window doc slice also, look at the documentation f...

plus de 8 ans ago | 0

Simpson's Rule Illustration - How to create those parabolas?
here is what I have done <<http://snag.gy/cjsli.jpg>> clc;clear; close all x = linspace(0,4*pi); % create data ...

plus de 8 ans ago | 1

How to solve max load of P in Matlab?
So, when I see a problem statement that says "solve the above system of equations" I think of formulating the equations in matri...

plus de 8 ans ago | 1

Want to make linear fitting and plot both graph on the same curve
you are going to have to transform your data: x=[0;0.100000000000000;0.200000000000000;0.300000000000000;0.40000000000000...

plus de 8 ans ago | 0

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Solving for a data point
pt2pt1 = @(M)(((y+1)*M^2)/((y-1)*M^2+2))^(y/(y-1))*((y+1)/(2*y*M^2-(y-1)))^(1/(y-1))-.6925 fsolve(pt2pt1,2)

plus de 8 ans ago | 0